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Ostrovityanka [42]
3 years ago
15

Solve for x & y: x^2+y^2=20. 3x+y=2

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0
You're solving a system here, easy peasy. Solve the second equation for y to get y = 2 - 3x. Now in the first equation, sub in this y value where you see a y and now the equation is in terms of x only: x^2 + (2-3x)^2 = 20. You have to FOIL out the (2-3x)^2 first to get x^2 + 4 - 12x + 9x^2 = 20. Now combine like terms to get 10x^2 - 12x + 4 = 20. Move the 20 over by subtraction to get
10x^2 - 12x - 16 = 0. Factor this now, taking a 2 out first: 2(5x^2 - 6x -8)=0 and you get factors of 2(x-2)(5x+4)=0. x=2 or x = -4/5. If x = 2, then y = -4. If x = -4/5, then y = 22/5
Lerok [7]3 years ago
5 0

Answer:

1

Step-by-step explanation:


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Arisa [49]

Answer:

C

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ), thus

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7 0
3 years ago
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Ilya [14]

Answer:

\boxed{\sf sin\ C =\frac{40}{41}}

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}

Substitute the respective values ,

\sf\longrightarrow \boxed{\blue{\sf sin\ C =\dfrac{40}{41}}}

<u>Hence the required answer is 40/41.</u>

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3 years ago
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Answer:

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Step-by-step explanation:

-103 + (-104)

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= -207.

3 0
3 years ago
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