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ryzh [129]
3 years ago
7

In 1787,_________discovered a relationship between charge, their separation, and the force between the two charges. A coulomb B

Newton C Gilbert
Chemistry
1 answer:
masya89 [10]3 years ago
7 0

The answer is A. Columb

Columb discovered a relationship between charge, their speration, and the force between the two charges in 1787

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Earth's Revolution question:
Murljashka [212]

Answer:

itos6oyoyoydkgzkstgjuf

7 0
3 years ago
1) When 2.38g of magnesium is added to 25.0cm of 2.27 M hydrochloric acid, hydrogen gas is released.
Andrej [43]

Answer:

a. HCl.

b. 0.057 g.

c. 1.69 g.

d. 77 %.

Explanation:

Hello!

In this case, since the reaction between magnesium and hydrochloric acid is:

Mg+2HCl\rightarrow MgCl_2+H_2

Whereas there is 1:2 mole ratio between them.

a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:

n_{H_2}^{by\  HCl}=0.025L*2.27\frac{molHCl}{1L}*\frac{1molH_2}{2molHCl}  =0.0284molH_2\\\\n_{H_2}^{by\  Mg}=2.38gMg*\frac{1molMg}{24.3gMg}*\frac{1molH_2}{1molMg}=0.0979molH_2

Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.

b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:

m_{H_2}=0.0284molH_2*\frac{2.02gH_2}{1molH_2}=0.057gH_2

c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:

m_{Mg}^{reacted}=0.0284molH_2*\frac{1molMg}{1molH_2}*\frac{24.3gMg}{1molMg}  =0.690gMg

Thus, the mass of excess magnesium turns out:

m_{Mg}^{excess}=2.38g-0.690g=1.69gMg

d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:

Y=\frac{0.044g}{0.057g} *100\%\\\\Y=77\%

Best regards!

8 0
3 years ago
4. Write the chemical equation for the reaction that occurs when baking soda (NaHCO3) is
aev [14]

Answer: HCl+NaHCO₃=NaCl+CO₂+H₂O

Explanation:

3 0
3 years ago
39. Consider the following molecules:
sweet [91]
I) cc14
ii) h20
iii) i’m not sure

not fully sure but hope this helps!
5 0
3 years ago
Which nonmetal would an ion of Ca2+ MOST LIKELY ionically bond with in a 1:1 ratio? A) one atom of neon B) one atom of carbon C)
GalinKa [24]
Ca2+ would bond to any element in a 1 to 1 ratio that had an equal and opposite charge.

Neon is a noble gas, and doesn’t form bonds m

Carbon isn’t typically found in ion state, but if it did, it would likely by C4+

Flouring in ionic state is F1-, so you would need 2 flourines to cancel the 2+ charge of Calcium

Then the only option left would be Oxygen which, when in ion form is found be 2-
5 0
3 years ago
Read 2 more answers
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