K₃PO₄ → 3K⁺ + PO₄³⁻
PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻
HPO₄²⁻ + H₂O ⇄ H₂PO₄⁻ + OH⁻
H₂PO₄⁻ + H₂O ⇄ H₃PO₄ + OH⁻
K⁺, PO₄³⁻, HPO₄²⁻, H₂PO₄⁻, OH⁻
Answer:
The mass percentage of nitrogen in the sample is 1.96%.
Explanation:
21.0 mL of 0.150 M HCl
Moles of hydrogen chloride = n
Volume of hydrogen chloride solution = 21.0 mL = 0.021 L
Molarity of the hydrogen chloride = 0.150 M


According to recation, 1 mole of HCl neutralizes 1 mole ammonia.Then 0.00315 moles of HCl will neutrtalize:
of ammonia
1 mole of ammonia has 1 mole of nitrogen atom . Then 0.00315 moles of ammonia will have = 1 × 0.00315 mol = 0.00135 mol
Mass of 0.00315 moles of nitrogen= 0.00315 mol × 14 g/mol = 0.0441 g
Mass of the sample = 2.25 g
The mass percentage of nitrogen in the sample:

Answer:

Explanation:
Hello there!
In this case, since the Kp for the first reaction is given, according to the following equilibrium expression:

However, since the second reaction stands for the reverse of the initial one, the equilibrium expression would be:

And therefore its Kp the inverse of the aforementioned one:

Best regards!