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Kaylis [27]
3 years ago
13

The final cost of a sale item is determined by multiplying the price on the tag by 75%. Which best describes the function that r

epresents the situation?
Mathematics
2 answers:
lara [203]3 years ago
7 0
Discount, as you are lowering the item price from 100%  (Default ) to 75% 


Discount = 100% - 75% = 25%

If it was required to find the discount.

discount = 0.25 x Price.

newPrice = 0.75 x Price

Original price = Discount + new Price. 
marissa [1.9K]3 years ago
7 0

Answer: It is linear because the ratio of the change in the final cost compared to the rate of change in the price tag is constant

Step-by-step explanation:

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How can you divide 3 4 by 65
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Answer:

48 3/4

Step-by-step explanation:

65/1

3 x65/4x1=195/4 which equal 48 3/4

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Kenya exchanges $150 for British pounds(£). Suppose the conversion rate is £1 = $1.60. How many pounds should she receive?
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If $1.60 is 1 pound, divide the $ amount by 1.60 to find the number of pounds. 150/1.6 = 93.75
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Identify a number that results in a 4-digit-number when 156,350 is subtracted from it
jekas [21]

160,000 - 156,350 =3,650

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3 years ago
-3b+7=13 solve for b
sleet_krkn [62]

Answer:

b =-2

Step-by-step explanation:

-3b+7=13

Subtract 7 from each side

-3b+7-7=13-7

-3b = 6

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On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

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3 years ago
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