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Nimfa-mama [501]
3 years ago
7

A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase,

the company asked the manufacturer to provide data on a certain machine's efficiency. The data suggests that with a supplied energy at a rate of 1600 w, the machine will do useful work at a rate of 1540 w. What's the efficiency of this particular machine
Physics
2 answers:
Helen [10]3 years ago
8 0
The mechanical efficiency = actual work / ideal work

So ζ = 1540 / 1600 * 100% = 96.25%
s2008m [1.1K]3 years ago
4 0

Answer:

96.25%

Explanation:

You might be interested in
Describe the motion of an object that has an acceleration of 0 mi./s squared
miskamm [114]
The object does not move.
5 0
3 years ago
It takes 15 min to drive 6.0 mi in a straight line to the local hospital. It takes 10 min to go the last 3.0 mi, 2.0 min to go t
Gala2k [10]

Answer:

36.87 km/h

Explanation:

Convert all the units in SI system

1 mile = 1609.34 m

d1 = 6 mi = 9656.04 m

t1 = 15 min = 15 x 60 = 900 s

d2 = 3 mi = 4828.02 m

t2 = 10 min = 10 x 60 = 600 s

d3 = 1 mi = 1609.34 m

t3 = 2 min = 2 x 60 = 120 s

d4 = 0.5 mi = 804.67 m

t4 = 0.5 min = 0.5 x 60 = 30 s

Total distance, d = d1 + d2 + d3 + d4

d = 9656.04 + 4828.02 +  1609.34 + 804.67 = 16898.07 m = 16.898 km

total time, t = t1 + t2 + t3 + t4

t = 900 + 600 + 120 + 30 = 1650 s = 0.4583 h

The ratio of the total distance covered to the total time taken is called average speed.

Average speed = 16.898 / 0.4583 = 36.87 km/h

6 0
3 years ago
Gumuhit ng paglalaruan ng<br>agawang sulok at ibigay ang bawat<br>sukat nito.​
Anarel [89]

Answer:

there's a link to answer

Explanation:

there's a link to answer in another's persons response it helps a lot just click on it

8 0
3 years ago
Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr
Sedbober [7]

Answer:

(A) ratio of electric force to weight will be  23.469\times 10^{-10}

(b) Electric field will be E=4.26\times 10^{10}N/C

Explanation:

We have given mass of bee = 100 mg  = m=100\times 10^{-3}=0.1kg

Charge on bee q=23pC=23\times 10^{-12}C

Electric field E = 100 N/C

Weight of the bee W=mg=0.1\times 9.8=0.98N

Electric force on the bee F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N

So the ratio of electric force on the bee and weight is =\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}

(B) To hold the bee in air electric force must be equal to weight of bee

So mg=qE

0.1\times 9.8=23\times 10^{-12}E

E=4.26\times 10^{10}N/C

4 0
3 years ago
How much work done when .0080 C is moved through a potential difference of 1.5 V? Use W = qV. A.
grin007 [14]

Answer:

0.012 J

Explanation:

We are given:

q = 0.0080C

Potential difference =  1.5V

W=qV

Substituting the values into the equation:

W=0.0080*1.5= 0.012J

8 0
3 years ago
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