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Bas_tet [7]
3 years ago
9

a fly wheel is rotating with an angular velocity of 2 rad/sec and acted by an acceleration of 1/π rad/s2 . how long will it take

to complete three revolutions?​
Physics
1 answer:
Nitella [24]3 years ago
4 0

Explanation:

this is the answer for your question if you have any doubt you can join

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Inessa05 [86]

Answer:

Explanation:

the yellow box is -5

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"Influence" between bodies is reduced as the bodies are
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Both particles and big objects will be influenced by each other less if they are moved further apart. 
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A uniform rod is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The moment of inertia of t
emmasim [6.3K]

Answer:

Angular acceleration = 6.37rad/sec²

Approximately, Angular acceleration =

6.4 rad/sec²

Explanation:

Length of the rod = 2.0m long

Inclination of the rod (horizontal) = 30°

Mass of the rod is not given so we would refer to it as = M

Rotational Inertia of the Rod(I) = 1/3ML²

Angular Acceleration = ?

There is an equation that shows us the relationship between Torque and Angular acceleration.

The equation is :

Torque(T) = Inertia × Angular Acceleration

Angular acceleration = Torque ÷ Inertia

Where:

Torque = L/2(MgCosθ)

Where M = Mass

L = Length = 2.0m

θ = Inclination of the rod (horizontal) = 30°

g = Acceleration due to gravity = 9.81m/s²

Inertia = 1/3ML²

Angular Acceleration =  (Mass × g × Cos (30°) × (L÷2)) ÷ 1/3ML²

Angular Acceleration =

(3 × g × cos 30°) ÷ 2× L

Angular Acceleration = (3 × 9.81m/s² × cos 30°) ÷ 2× L

Angular Acceleration = 3 × 9.81m/s² × cos 30°) ÷ 2× 2.0m

Angular Acceleration = 6.37rad/sec²

Approximately Angular Acceleration =

6.4rad/sec²

5 0
3 years ago
You have been hired by a "storm chaser" as an assistant. This individual loves to find locations at which tornadoes and violent
Studentka2010 [4]

Answer:

58.44 C

Explanation:

Electric field is found by

E=\frac {\sigma}{\epsilon_o}=\frac {Q}{A\epsilon_o}

Therefore, the charge is

Q=EA\epsilon_o


Q= 4.00 ✕ 10^{6} N/C*1.65 *10^{6} m^{2}*8.854*10^{-12}= 58.4364 C


Therefore, required charge is 58.44 C

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