Answer:
Explanation:
The period of oscillation is given as
T=2π√m/k
Making k subject of the formula
Square both sides of the equation
T²=4π²(m/k)
Cross multiply
T²k=4π²m
Then, divide through by T²
k=4π²m/T²
Where
k is spring constant
m is the mass of the bob
And T is the period of the oscillation
m=140g=0.14kg
14 oscillations takes 14 seconds
Then the period is
T=time/oscillation
T=14/14
T=1sec
Then,
k=4π²m/T²
k=4π²×0.14/1²
k=1.76N/m
Then, the spring constant is 1.76N/m
The answer is SHORT CIRCUIT
Answer:
In a way of energy “1s” subsell contains most energy. because 1 s subsell contains the electrons of K orbital which is nearest from the nucleus. so the order of energy will be 1s>2s>2p> 3s> 3p> 4s> 3d> 4p> 5s> 4d> 5p> 6s> 4f> 5d> 6p> 7s and the increasing order of thair energies will be- 4s <3d<4p<5s<4d<5p<6s<4f.
+10m/s²--25m/s
Explanation:
it's downward acceleration is +10ms-²
since it is falling freely under the influence of gravity
Since the elevator drops downward, that is initially from rest , u=0
so for this equation S=u + ½at²
but since u is 0 the new equation becomes S=½at²
thus from the new equation we determine the height attained after 2.5s during the fall
substituting 2.5s in the equation...
we get s to be 31.25m
then we substitute s in this equation when u=0 to get the velocity of the body
v²=u²+2as
v²=2as
v²=2(+10•31.25)
v²=625
v=25m/s
i suppose this will help
Answer:
The stones are apart one each the other 26.37 meters when the second one has reached a speed of 14 m/s.
Explanation:
<u>Second Stone:</u>
Vb= g*t
tb (14m/s)= Vb/g
tb (14m/s)= (14 m/s) / (9.8 m/s²)
tb (14m/s)= 1.42 sec
Hb= (g * tb²)/2
Hb= 9.88m
<u>First Stone:</u>
ta= tb + 1.3 sec
ta= 2.72 sec
Ha= (g*ta²)/2
Ha= 36.25m
Distance between Stones:
Ha-Hb= 36.25m - 9.88m
Ha-Hb= 26.37m