Answer:
Joules=F*d, watts= J/s, Kwh= kw*h(time)
Explanation:
First, we need to know... what are we measuring with the different units:
Joules: This unit is used to measure energy and work.
![EnerKinec=\frac{1}{2} * m[kg]*v^{2} [m^{2}/s^{2} ]\\\\Enpot=m[kg]*g[m/s^{2}]*h[m]\\ \\Work=F[N]*d[m]](https://tex.z-dn.net/?f=EnerKinec%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%20m%5Bkg%5D%2Av%5E%7B2%7D%20%5Bm%5E%7B2%7D%2Fs%5E%7B2%7D%20%20%5D%5C%5C%5C%5CEnpot%3Dm%5Bkg%5D%2Ag%5Bm%2Fs%5E%7B2%7D%5D%2Ah%5Bm%5D%5C%5C%20%5C%5CWork%3DF%5BN%5D%2Ad%5Bm%5D)
Watts: This unit is used to measure power, and is related to energy and work when we use the time. That is, power equals work or energy per unit of time.
![Power = \frac{work[J]}{time[s]} = [watts]](https://tex.z-dn.net/?f=Power%20%3D%20%5Cfrac%7Bwork%5BJ%5D%7D%7Btime%5Bs%5D%7D%20%3D%20%5Bwatts%5D)
KWh: This unit is used to measure the amount of power consumed, it is very common to see it on electric energy bills.
![Powerconsumed=Power*hoursworked\\\\Powerconsumed= power[kw]*hoursworked[hr]=[Kw-h]](https://tex.z-dn.net/?f=Powerconsumed%3DPower%2Ahoursworked%5C%5C%5C%5CPowerconsumed%3D%20power%5Bkw%5D%2Ahoursworked%5Bhr%5D%3D%5BKw-h%5D)
Momentum, p=mass* velocity
P=2250(25)
p=56250 kgm/s
Hope this can help.
Answer:
The cable run exceeds the specifications for Ethernet over twisted pair
Explanation:
The ethernet network's router also serves as a bridge to the Internet. The router connects to the modem, which carries the Internet signal, sending and receiving data packet requests and routing them to the proper computers on the network.
Ethernet is a way of connecting computers together in a local area network or LAN. It has been the most widely used method of linking computers together in LAN s since the 1990 s.
The basic idea of its design is that multiple computers have access to it and can send data at any time.
The initial compression of the spring is determined as 0.54 m.
<h3>What is the compression of the spring?</h3>
The compression of the spring is determined by applying the principle of conservation of linear momentum as follows;
E = U
mgh = ¹/₂kx²
2mgh = kx²
x² = 2mgh/k
x = √(2mgh/k)
where;
- m is the mass of the projetcile
- h is the height
- k is the spring constant = 0.07 N/cm = 7 N/m
- x is the compression of the spring
x = √(2 x 0.021 x 9.8 x 5)/7)
x = 0.54 m
Learn more about compression of spring here: brainly.com/question/2114706
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Answer:
120,000seconds
Explanation:
400 minutes x 5= 2000minutes (2000minutes x 60)seconds =120,000seconds.
btw :
stay safe! :3