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4 years ago

Floodplains are most often found for rivers that exist on

Physics

2 answers:

Schach [20]4 years ago

4 0

Answer:

areas that get high rainfall... im pretty sure

Explanation:

Kazeer [188]4 years ago

3 0

I am pretty sure that floodplains are most often found for rivers that exist on <span>
hilly areas at the base of mountains. In order to give yoy ans example which will make sure that this answer is quite a suitable one, nice example of f</span><span>loodplains</span>
is The Virgin River<span> at the upper end of Zion Canyon. It will definitely help you! Regards.</span><span>

</span>

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The displacement z of a particle of rest mass m0, resulting from a constant force m0g along the z-axis is including relativistic

Debora [2.8K]

Hi, your question was incomplete, hence I am writing down the complete question below.

Q)The displacement x of a particle of rest mass m0, resulting from a constant force m0g along the x-axis, is

x= c2/g{[1+(gt/c)2]power0.5-1}

including relativistic effects. Find the displacement x as a power series in time t. Compare with the classical result.

Answer:

<h3>Please refer to the attachment below.</h3>

Explanation:

<h3>Please refer to the attachment below for explanation.</h3>

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3 years ago

420 hg = _____ cg help please

kondaur [170]

4200000 is your answer hope this helps

4 0

4 years ago

Read 2 more answers

Two speakers that are 12.0 m apart produce in-phase sound waves of frequency 245 Hz in a room where the speed of sound is 340 m/

Cerrena [4.2K]

Answer:

a) Please see below as the answer is self-explanatory

b) 0.35 m

c) 0.7 m

Explanation:

a) As there is no difference in the path (because she is exactly at the midpoint between both speakers) that the waves do in order to reach to her ear, she listens both waves with the same intensity.

The same effect would be experimented, if the difference between paths, were an even multiple of the half of the wavelength.

b) In order to have a destructive interference, the difference in path (in the worst case) must be equal to an odd multiple of the half wavelength.

In any wave, there is a fixed relationship between speed, frequency and wavelength, as follows:

λ = v / f

Replacing with our givens for frequency (245 Hz) and v (340 m/s), we have:

λ = 340 m/s / 245 Hz = 1.4 m

The condition for destructive interference, is as follows:

Δd = d₂-d₁ = (2n + 1) *λ/2

For n=0, we have the shortest distance:

Δd = λ/2 = 0.7 m

So, in order to have such a path difference, she must walk exactly the half of this distance from the center, i.e., 0.35 m.

c) With the same reasoning as above, as the condition for constructive interference, as we have already mentioned, is that the path difference be at least one full wavelength, we can say:

Δd = d₂-d₁ = λ

So, in order to have such a path difference, she must walk exactly the half of this distance from the center, i.e., 0.7 m.

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3 years ago

Qualitative and Quantitative Momentum Problems.

Elena L [17]

Answer: the reaction force is large.

Explanation:

From Newton's third law, we know that for every action, there is equal and opposite reaction.

Since, a large amount of high speed of water is ejecting out from hose. The high momentum due to large speed in short duration of time would cause water to eject out with great force. The reaction force would act on the firefighter holding the hose. An equal amount of large force would act on him. Thus, it is difficult for a firefighter to hold a hose that ejects large amounts of high speed water.

3 0

4 years ago

Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic

olga_2 [115]

Answer:

h = 1.01 x 10⁻³⁴ J.s

Explanation:

The energy applied by the voltage must be equal to the energy associated with the wavelength of light:

$eV = \frac{hc}{\lambda}\\$

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = stopping potential

h = Planck's Constant = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light

For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:

$(1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\$

h = 1.49 x 10⁻³⁴ J.s

For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:

$(1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\$

h = 0.53 x 10⁻³⁴ J.s

Taking average of both values:

$h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}$

3 0

3 years ago