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alekssr [168]
3 years ago
12

You want to build a search light. The search light is to have an outgoing parallel beam. You have a small, very bright light (a

point light source) and a concave mirror with radius of curvature 2m. How far from the mirror should the point light source be placed so the mirror produces an outgoing parallel beam
Physics
1 answer:
andrew11 [14]3 years ago
3 0

Answer:

1 m                              

Explanation:

Given

The mirror is a concave mirror.

Radius of curvature = 2 m

Now, for a parallel beam after reflection  occurs, the object should be placed at the focus of the mirror.

We know, focal length = radius of curvature / 2

                                      = 2 / 2

                                      = 1

Thus the focal length is 1 m.

Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.

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15 points! An atomic nucleus initially moving at 420 m/s emits an alpha particle in the direction of its velocity, and the remai
alexandr1967 [171]

The alpha particle is emitted at 4235 m/s

Explanation:

We can use the law of conservation of momentum to solve the problem: the total momentum of the original nucleus must be equal to the total momentum after the alpha particle has been emitted. Therefore:

p_i = p_f\\ Mu=m_1 v_1 + m_2 v_2 =  

where:  

M =222u is the mass of the original nucleus

v=420 m/s is the initial velocity of the nucleus

m_1 = 4 u is the mass of the alpha particle

v_1 is the final velocity of the alpha particle

m_2 = 222u-4u = 218 u is the mass of the daughter nucleus

v_2 = 350 m/s is the final velocity of the nucleus

Solving for v_1, we  find the final velocity of the alpha particle:

v_1 = \frac{Mu-m_2 v_2}{m_1}=\frac{(222)(420)-(218)(350)}{4}=4235 m/s

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3 years ago
In science, a broad idea that has been repeatedly verified so as to give scientists great confidence that it represents reality
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In science, a broad idea that has been repeatedly verified so as to give scientists great confidence that it represents reality is called "a theory".

<u>Explanation:</u>

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6 0
3 years ago
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
Viktor [21]

Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

Weight of the object, W = 2.45 N

Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

Spring constant of the spring.

Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

m is the mass of object

m=\dfrac{W}{g}

m=\dfrac{2.45}{9.8}

m = 0.25 kg

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.25}{(0.64)^2}

k = 24.09 N/m

or

k = 24.11 N/m

So, the spring constant of the spring is 24.1 N/m.

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How dose silicon shape our technological reality?
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