∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
Learn more about similar triangles here:
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C for change it is kinda obvious because change starts with a c and apples start with an a and bananas start with a b
Answer:40
Step-by-step explanation: i may be wrong but i subtracted 136 from 95 and i got 40 im sorry if it is wrong
we know that
arithematic sequence will always have common difference
(a)
−5, −7, −10, −14, −19, …
we can see that
they are not equal
so, this is not arithematic sequence
(2)
1.5, −1.5, 1.5, −1.5, …
we can see that
they are not equal
so, this is not arithematic sequence
(3)
4.1, 5.1, 6.2, 7.2, …
we can see that
they are not equal
so, this is not arithematic sequence
(4)
−1.5, −1, −0.5, 0, …
we can see that
they are equal
so, this is arithematic sequence
7. x=3 is the midpoint between the roots. The other root is x = 2*3 -(-5) = 11.
8a) f(x) = (x +3)^2 -49. The vertex is (-3, -49). The roots are -10, 4.
8b) y = (x+4)^2 -1. The vertex is (-4, -1). The roots are -5, -3.
8c) f(x) = 2(x +3)^2 -34. The vertex is (-3, -34). The roots are -3±√17.
