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Ivahew [28]
3 years ago
11

Fine Floors can install 15 square yards of carpeting in 4 hours and 30 minutes. At this rate, how long would it take to install

carpeting in a room that measures 11 feet 9 inches by 13 feet 4 inches?
A.) 4 hours
B.) 5.5 hours
C.) 58 hours
D.) 5 hours, 13 minutes
Mathematics
2 answers:
Pie3 years ago
4 0

Answer:

yes the correct answer is D

Step-by-step explanation: First, find the area of the new room and convert it to square yards. Then, set up a proportion to compare the amount of time it take to install 15 square yards with the new amount.

AnnZ [28]3 years ago
3 0
D is your awnser here
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The new patio at Tonya's house is 5 yards long by 10 feet wide. She is going to cover the patio with square bricks that measure
Klio2033 [76]

Answer:

A

Step-by-step explanation:

Steps to take to determine the answer

  1. Because the length is in yards, it has to be converted to foot
  2. Find the area of the patio using the length and width measured in foot
  3. Determine the area of the square brick
  4. Multiply the cost of the brick by the area

1 yards = 3 foot

5 x 3 = 15 foot

Area of a rectangle = length x breadth

15 x 10 = 150 ft^2

Cost = 150 x 4 = $600

4 0
3 years ago
What’s 2.5 times 0.3 with four decimals places
aleksandr82 [10.1K]

\mathrm{Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer},25\cdot:3=75,2.5\mathrm{\:has\:}1\mathrm{\:decimal\:place},0.3\mathrm{\:has\:}1\mathrm{\:decimal\:place},\mathrm{Therefore,\:the\:answer\:has\:}2\mathrm{\:decimal\:places},=0.75

Hope This helps!!!

6 0
3 years ago
What is the approximate height of the hat?
alexira [117]
4th option because you use the pythagorean theorem so 16^2 - 7.4^2= 201.24
which equals approx 14.19
3 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
If (−7, m) is on a circle with center c(3, 5) and radius 10, what is the value of m? m = 5 m equals negative five plus two squar
AfilCa [17]

{(x - 3)}^{2}  +  {(y - 5)}^{2}  = 100 \\ 100 +  {(y - 5)}^{2} = 100 \\ y = 5
7 0
3 years ago
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