Tigers: 1 - 2/3 = .3333
Redbirds: 1 - 4/5 = .2
Bulldogs: 1 - 3/8 = .625
Titans: 1 - 1/2 = .5
The Redbirds likelyhood is lowest, therefore, they're least likely to play I'm the championship.
B is the correct answer.
Step-by-step explanation:
please i work on by paper worksheet, see it
how can i work it
10000+4.8%=10480
10480+4.8%=10983.04
10983.04+4.8%=11510.22592
so 3 years
Answer:
Mean of the data would be 6c
Step-by-step explanation:
<u>Rule to Remember:</u> Whenever each term of the data is multiplied by the same number, the new mean is previous mean multiplied by that number.
In this case, original value of mean was c. Each value of the data is multiplied with 6 so a result the new mean would be 6 times the original mean i.e. 6c
Let us consider that original values in the data set are x, y and z. Their mean would be:
If each value of the data is multiplied with 6, the new values would be 6x, 6y and 6z. The mean in this case will be:
We can see from above that the new mean is 6 multiplied to the original mean.
Therefore, the answer to this question is 6c.
The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.
The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.
This leaves us with the second choice. Recall that
1 + tan²(x) = sec²(x)
and the derivative of tangent,
(tan(x))' = sec²(x)
Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then
y' = sec²(x³/3 + 2) • x²
and substituting y and y' into the ODE gives
sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))
x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)
which is an identity.
So the solution is y = tan(x³/3 + 2).