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Dafna11 [192]
3 years ago
7

Please help me i gotta turn this in in 10 minutes

Mathematics
2 answers:
Marina CMI [18]3 years ago
4 0
To find the ratio, we must find the total amount of days (31) and the number of days that are either a Saturday or a Sunday (10). Since in the sentence, the number of Saturdays and Sundays is mentioned first, the 10 would precede the 31 in the ratio.

Final Answer - 10:31
nataly862011 [7]3 years ago
4 0
1) First figure out the number of days in August. This is easy because it's given to you - it's the number of days on the calendar, 31.

2) Next, count up the number of Saturdays and Sundays. There are 5 Saturdays + 5 Sundays = 10 total.

3) Finally put it as a ratio. Since you're looking for the ratio of "something" to "something," you want to put it as the first thing over the second thing (if in fraction form) or first thing:second thing. 

So Saturdays and Sundays to total number of days:
\frac{10}{31} or 10:31

------

Answer: \frac{10}{31} or 10:31
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D

Step-by-step explanation:

7 0
3 years ago
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Anyone know the answer?
sattari [20]
The answer is c because k and m are the same so l and n are also the same


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3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
When dividing the polynomial 3x3 - 5x2 - 4x + 4 by (x - 2), the remainder is 0, making (x - 2) a factor.
Ne4ueva [31]
(3x^3 - 5x^2 -4x + 4) / (x-2) = (3x-2)(x+1) when x ≠2
3 0
3 years ago
What is the solution to q+(-9)=12
Whitepunk [10]
<span><span>
q−9</span>=12

</span>Step 1: Add 9 to both sides.

<span><span><span>q−9</span>+9</span>=<span>12+9

</span></span><span>q=21

</span>Answer:

<span>q=21</span>
7 0
3 years ago
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