Answer:
Part 1) 
Par 2) 
Part 3) 
Step-by-step explanation:
step 1
Find the 
we have

Remember that

therefore

step 2
Find the 
we know that

we have

substitute




square root both sides

we have that
---> given problem
so

step 3
Find the 
we know that

we have


substitute

Simplify

Answer:
The total length of rebar used is 21.66 meters.
Step-by-step explanation:
Given:
Ivan had cut a reinforcing bar in 19 pieces and length of each bar is 1.14 meters.
Number of pieces = 19
Length of each piece = 1.14
We need to find the total length of reinforcing bar.
To calculate the total length we will multiply number of pieces with length of each piece.
Hence,
Total length of rebar = Number of pieces × Length of each piece = 
Rounding to nearest hundred = 21.66 m
Hence the total length of reinforcing bar is 21.66 meters.
Answer:
65°
Step-by-step explanation:
all angles in a trapezium equate to 360°
R is 115°
115+115=230
360-230=130
130÷2=65
Here, My initial salary = 7.85
FICA deduction amount = 7.85 * 7.65% = 7.85 * 0.0765 = 0.60
Federal Tax amount = 7.85 * 9.8% = 7.85 * 0.098 = 0.77
State tax amount = 7.85 * 5.5% = 7.85 * 0.055 = 0.43
So, Total deducted amount = 0.60 + 0.77 + 0.43 = 1.80
Net hourly wage = 7.85 - 1.80 = 6.05
In short, Your Answer would be $6.05
Hope this helps!
Answer:
- The solution that optimizes the profit is producing 0 small lifts and 50 large lifts.
- Below are all the steps explained in detail.
Explanation:
<u />
<u>1. Name the variables:</u>
- x: number of smaller lifts
- y: number of larger lifts
<u></u>
<u>2. Build a table to determine the number of hours each lift requires from each department:</u>
<u></u>
Number of hours
small lift large lift total per department
Welding department 1x 3y x + 3y
Packaging department 2x 1y 2x + y
<u></u>
<u>3. Constraints</u>
- 150 hours available in welding: x + 3y ≤ 150
- 120 hours available in packaging: 2x + y ≤ 120
- The variables cannot be negative: x ≥ 0, and y ≥ 0
Then you must:
- draw the lines and regions defined by each constraint
- determine the region of solution that satisfies all the constraints
- determine the vertices of the solution region
- test the profit function for each of the vertices. The vertex that gives the greatest profit is the solution (the number of each tupe that should be produced to maximize profits)
<u></u>
<u>4. Graph</u>
See the graph attached.
Here is how you draw it.
- x + 3y ≤ 150
- draw the line x + 3y = 150 (a solid line because it is included in the solution set)
- shade the region below and to the left of the line
- 2x + y ≤ 120
- draw the line 2x + y ≤ 120 (a solid line because it is included in the solution set)
- shade the region below and to the left of the line
- x ≥ 0 and y ≥ 0: means that only the first quadrant is considered
- the solution region is the intersection of the regions described above.
- take the points that are vertices inside the solutoin region.
<u>5. Test the profit function for each vertex</u>
The profit function is P(x,y) = 25x + 90y
The vertices shown in the graph are:
The profits with the vertices are:
- P(0,0) = 0
- P(0,50) = 25(0) + 90(50) = 4,500
- P(42,36) = 25(42) + 90(36) = 4,290
- P(60,0) = 25(60) + 90(0) = 1,500
Thus, the solution that optimizes the profit is producing 0 smaller lifts and 90 larger lifts.