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kotegsom [21]
3 years ago
13

Are plants abiotic or biotic

Chemistry
1 answer:
UNO [17]3 years ago
6 0
Hey there!


The answer is biotic! Biotic are all living factors in an ecosystem.


Hope this helped!
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A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
Over [174]
In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0
3 years ago
When lithium reacts with bromine to form the compound LiBr, each lithium atom:
yKpoI14uk [10]
(3) loses one electron and becomes positively charged 
Lithium has one valence electron and Bromine has seven. Therefore Lithium will give up its one to Bromine for both to have an octet 
5 0
3 years ago
Read 2 more answers
Abiotic factors are no living part of an environment. True or False​
oksian1 [2.3K]

Answer:

true

Explanation:

abiotic means nonliving and biotic means living

6 0
3 years ago
Read 2 more answers
Which of the following is an example of a compound?<br><br> CaCl2<br><br> Na<br><br> Nd<br><br> Cu
madam [21]
CaCl2

All of the other choices are elements
5 0
3 years ago
Functions of the following ingredients in the production of dairy products.ii. Enzyme in cheese​
Serjik [45]

Answer:

sugar in melk

Explanation:

cow eat sugar then make sugar :)

5 0
3 years ago
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