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kotegsom [21]
3 years ago
13

Are plants abiotic or biotic

Chemistry
1 answer:
UNO [17]3 years ago
6 0
Hey there!


The answer is biotic! Biotic are all living factors in an ecosystem.


Hope this helped!
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pH is a logarithmic scale used to indicate the hydrogen ion concentration, [H+], of a solution: pH=−log[H+] Due to the autoioniz
Sophie [7]

Answer:

pH = 2,4

Explanation:

pH is defined as a measure of acidity or alkalinity of a solution based on H⁺ concentration

The HCl dissociates in water thus:

HCl → H⁺ + Cl⁻

That means that moles of HCl are the same than H⁺.

0,35gHCl\frac{1mol}{36,46g} = 9,6x10⁻³ moles HCl ≡ moles H⁺

H⁺ molarity is: \frac{9,6x10^{-3}moles}{2,5L} = 3,84x10⁻³M

As pH = -log [H⁺]

<em>pH = 2,4</em>

I hope it helps!

7 0
3 years ago
Definition of periodic trends
Dmitriy789 [7]

Answer:

.Periodic trends are specific patterns in the properties of chemical elements that are revealed in the periodic table of elements. Major periodic trends include electronegativity, ionization energy, electron affinity, atomic radii, ionic radius, metallic character, and chemical reactivity.

7 0
4 years ago
What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?
Maru [420]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

<u>Step 1 :</u> Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

This means there is 0.05 mol per 100mL

e

<u>Step 2 </u>: calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

3 0
3 years ago
Read 2 more answers
A monoprotic weak acid when dissolved in water is 0.66% dissociated and produces a solution with a pH of 3.04. Calculate the Ka
raketka [301]

Answer:

Ka = 6.02x10⁻⁶

Explanation:

The equilibrium that takes place is:

  • HA ⇄ H⁺ + A⁻
  • Ka = [H⁺][A⁻]/[HA]

We <u>calculate [H⁺] from the pH</u>:

  • pH = -log[H⁺]
  • [H⁺] = 10^{-pH}
  • [H⁺] = 9.12x10⁻⁴ M

Keep in mind that [H⁺]=[A⁻].

As for [HA], we know the acid is 0.66% dissociated, in other words:

  • [HA] * 0.66/100 = [H⁺]

We <u>calculate [HA]</u>:

  • [HA] = 0.138 M

Finally we <u>calculate the Ka</u>:

  • Ka = \frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]} = 6.02x10⁻⁶
3 0
3 years ago
How is n1 in the Rydberg equation related to the quantum number n in the Bohr model?
gavmur [86]

Alove you!nswer:

Explanation545):

3 0
3 years ago
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