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masya89 [10]
3 years ago
10

Statements. If temperature is increased then the reaction will happen because

Chemistry
1 answer:
Serggg [28]3 years ago
4 0
Increasing the temperature of the system, will cause the equilibrium to shift toward the direction of the reaction that absorbs heat.
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650.J is the same amount of energy as? <br>2720cal<br>1550cal<br>650.cal<br>2.72cal
Oksi-84 [34.3K]

<u>Ans: 650 J = 155 calories</u>


<u>Given:</u>

Energy in joules = 650 J

<u>To determine:</u>

The energy in calories

<u>Explanation:</u>

1 joule = 0.2388 calories

Therefore, 650 joules = 0.2388 calories * 650 J/1 J = 155 calories

4 0
4 years ago
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Which term describes something that displays all the characteristics of life?
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3 years ago
a covalent bond forms a. when an element becomes a noble gas. b. when atoms share electrons. c. between metals and nonmetals. d.
marin [14]
(B)When atoms share electrons
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3 years ago
What items are true about a block of ice at -10°C as you continue to apply heat
zhenek [66]

1. its temperature will rise continuously until it melts

I don't believe that any of the other answers are correct because it can not stay at a certain temperature if it is melting

5 0
3 years ago
Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ∆H° for the r
Kazeer [188]

Answer:

∆H° rxn = - 93 kJ

Explanation:

Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds  broken minus bonds formed (H according to Hess Law.

We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.

              N₂ (g)   +            3H₂ (g)   ⇒                          2NH₃ (g)

1 N≡N = 1(945 kJ/mol)     3 H-H = 3 (432 kJ/mol)       6 N-H = 6 ( 389 kJ/mol)

∆H° rxn = ∑  H bonds broken  - ∑ H bonds formed

∆H° rxn = [ 1(945 kJ)   + 3 (432 kJ) ] - [ 6 (389 k J]

∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ

be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond,  N≡N,  we have to use this one .

8 0
3 years ago
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