The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L
<h3>Balanced equation</h3>
2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
Therefore,
12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂
<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>
At standard temperature and pressure (STP),
1 mole of C₂H₂ = 22.4 L
Therefore,
6 moles of C₂H₂ = 6 × 22.4
6 moles of C₂H₂ = 134.4 L
Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L
Learn more about stoichiometry:
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