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IRINA_888 [86]
3 years ago
15

A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 36 gram sample of this isotope is allowed to decay fo

r 80 minutes, how many grams of the radioactive isotope will remain?
Chemistry
1 answer:
lawyer [7]3 years ago
5 0
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58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,
erica [24]

<em><u>Answer and Explanation:</u></em>

Greetings!

Let's~answer~your~question!

Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.

\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}

<em><u>For % of N2 gas: </u></em>

<em><u /></em>100\% - (5\% + 12\%) = 83\% ~N2<em><u /></em>

<em><u /></em>

<em><u /></em>PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm<em><u /></em>

<em><u /></em>PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm<em><u /></em>

<em><u /></em>~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm<em><u /></em>

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4 years ago
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Klio2033 [76]

Answer:

Explanation:

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3 years ago
Research about the reaction of baking soda and vinegar
Stells [14]
Baking soda and vinegar react because of an acid-base reaction. The product of this creates carbon dioxide.
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C) Do grits work better at killing fire ants than commercial products?
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6 0
3 years ago
*explain your answer for brainliest
Over [174]

Answer:

3 mol Cl₂/2 mol AlCl₃ (three over two)

Step-by-step explanation:

Start with the balanced equation"

2Al + 3Cl₂⟶ 2AlCl₃

The steps in the calculation are

mass of AlCl₃ ⟶ moles of AlCl₃⟶ moles of Cl₂ ⟶ mass of Cl₂

The critical step is the <em>conversion of moles</em>.

You multiply the moles of AlCl₃ by a <em>conversion factor</em> to get moles of Al:

Moles of AlCl₃ × conversion factor = moles of Al.

The conversion factor is <em>the molar ratio</em>, and it uses the coefficients of the formulas in the balanced equation.

It is either (2 mol AlCl₃/3 mol Cl₂) or (3 mol Cl₂/2 mol AlCl₃).

You choose the one that has the desired units of the answer in the numerator.

We choose the second option, because it has the correct units.

For example,

\text{0.2 mol AlCl}_{3} \times \frac{3\textbf{ mol Cl}_{2} }{ 2\text{ mol AlCl}_{3} } = 0.3\textbf{ mol Cl}_{2})

Notice how the units "mol AlCl₃" cancel and the correct units appear in the answer.

If we had used the other conversion factor, we would have gotten the wrong units.

3 0
3 years ago
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