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Anastaziya [24]
2 years ago
10

How many moles of solute are present in .75 l of a .89 m (molar) solution?

Chemistry
1 answer:
never [62]2 years ago
8 0

0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.

<h3>Define the molarity of a solution.</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution.

Given data:

V= 0.75

M=0.89

Molality = \frac{Moles \;solute}{Volume of solution in litre}

0.89 M=  \frac{Moles \;solute}{0.75 L}

Moles= 0.6675

Hence, 0.6675 moles of solute are present in .75 l of a .89 m (molar) solution.

Learn more about the moles here:

brainly.com/question/24081006

#SPJ1

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Answer:

The answer to your question is C₂HO₃

Explanation:

Data

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Process

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2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

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3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

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Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

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