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Zepler [3.9K]
2 years ago
9

How many grams of potassium chloride, KCl, must be dissolved in 500.0 mL of solution to produce a 1.5 M solution?

Chemistry
1 answer:
denis23 [38]2 years ago
3 0

Answer:

How many grams of potassium chloride, KCl, must be dissolved in 500.0 mL of solution to produce a 1.5 M solution? Answer: g 4. What is the molarity of a solution in which 84.0 grams of sodium chloride, NaCl, is dissolved in 1.25 liters of solution? Answer: M 5.

Explanation:

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Answer:

temporary changes are the changes which are there only for a short period if time.

Explanation:

generally temporary changes are reversible. permanent changes are the changes which remain for a longer time and are not reversible

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Please be specific. Which umbrella?
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3 years ago
002 (part 1 of 2) 10.0 points
BARSIC [14]

Answer:

4) 1.5 mol

Explanation:

Well, the equation is already balanced and the mole to mole ratio of reactants and products are all 1. So if the limiting reactant is HCl and you have 1.5 mol, you do the mole to mole ratio with NaCl and since it is 1 to 1, there'd be 1.5 mol of NaCl.

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3 years ago
Find the volume of 56.0 grams of O2
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Answer:

39.2 L at STP

Explanation:

Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.

= 39.2 L

5 0
3 years ago
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
lions [1.4K]

Answer:

m=33.9g

Explanation:

Hello,

In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J

Afterwards, the mass of ice that can be melted is computed by:

Q=n \Delta _{fus}H

So we solve for moles with the proper units handling:

n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol

Finally, with the molar mass of water we compute the mass:

m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g

Best regards.

7 0
3 years ago
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