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ozzi
3 years ago
10

A bowl of trail mix and a bowl of soup are examples of what type of matter? 9 (a) solution (b) heterogeneous mixture (c) element

(d) compound
Chemistry
2 answers:
AleksandrR [38]3 years ago
6 0
The answer should be B.
Nostrana [21]3 years ago
5 0
B. heterogeneous mixture
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Convert 6.93 x 1024 atoms of carbon to moles of carbon.
Aleksandr [31]

Answer: 11.5 moles of carbon

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of carbon = 6.02 x 10^23 atoms

Z moles = 6.93 x 10^24 atoms

To get the value of Z, cross multiply:

(6.93 x 10^24 atoms x 1mole) = (6.02 x 10^23 atoms x Z moles)

6.93 x 10^24 = (6.02 x 10^23 x Z)

Z = (6.93 x 10^24) ➗ (6.02 x 10^23)

Z = 1.15 x 10

Z = 11.5 moles

Thus, there are 11.5 moles of carbon.

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3 years ago
From these four cycles which are water cycle, carbon cycle, nitrogen cycle, and phosphorus cycle which cycle has more nutrients
agasfer [191]

Answer:

Nitrogen cycle

Explanation:

7 0
3 years ago
What are 3 elements similar to silver
sesenic [268]
Are there any options?
3 0
3 years ago
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9.11 x 10^3 in standard notation?
Irina18 [472]

Answer:

the right answer is 9110

3 0
3 years ago
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An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
Lera25 [3.4K]

Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

K=394.53

By putting the values of K in equation 1

163=\sigma_o+\dfrac{394.53}{\sqrt 35}

\sigma_o\ =96.31\ MPa

\sigma_y=96.31+\dfrac{394.53}{\sqrt d}

Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

4 0
3 years ago
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