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Mashutka [201]
3 years ago
11

A gas that has a volume of 28 liters, a temperature of 42°C, and an unknown pressure has its volume increased to 49 liters and i

ts temperature decreased to 27°C. If the pressure is measured after the change at 4.0 atm, what was the original pressure of the gas?
Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

7.35 atm

Explanation:

From the question we are given;

  • Initial volume, V1 as 28 L
  • Initial temperature, T1 as 42°C or 315 K
  • New volume. V2 as 49 L
  • New temperature, T2 as 27°C  or 300 K
  • New Pressure, P2 as 4.0 atm

We are required to determine the initial pressure, P1

We are going to use the combined gas law...

According to the combined gas law,

\frac{P_{1} V_{1} }{T_1} =\frac{P_2V_2}{T_2}

Therefore, to get P1

P_1=\frac{P_2V_2T_1}{V_1T_2}

We get;

P_1=\frac{(4.0)((49)(315)}{(300)(28)}

P_1=7.35

Therefore, the initial pressure of the gas is 7.35 atm

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