Two changes would make this reaction reactant-favored
C. Increasing the temperature
D. Reducing the pressure
<h3>Further explanation</h3>
Given
Reaction
2H₂ + O₂ ⇒ 2H₂0 + energy
Required
Two changes would make this reaction reactant-favored
Solution
The formation of H₂O is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature rises, the equilibrium will shift towards the endothermic reaction, so the reaction shifts to the left towards H₂ + O₂( reactant-favored)
And reducing the pressure, then the reaction shifts to the left H₂ + O₂( reactant-favored)⇒the number of coefficients is greater
<span>Glycerol is a sub-unit molecule of a Lipid
So, option C is your answer.
Hope this helps!
</span>
Answer:
The answer to your question is the original dose of Ba-142 was 1184 μg
Explanation:
Data
Total time = 1.25 hours
The Final amount of Ba = 9.25 μg
The Half-life of Ba = 10.6 minutes
Process
1.- Convert total time to minutes
1 h ----------------- 60 min
1.25 h ------------ x
x = 75 min
2.- Draw a table of this process
Final amount of Ba Time
9.25 75 min
18.5 64.4 min
37 53.8 min
74 43.2 min
148 32.6 min
296 22 min
592 11.4 min
1184 0.8 min
There are two oxygen atoms in an oxygen molecule. Denoted by the 2 following O
