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mina [271]
3 years ago
7

Write the following inequality in slope-intercept form. −6x + 2y ≤ 42

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0
Add the 6x to both sides. Then divide both sides by 2 to get y by itself.

y <= 6x + 42

Note: if it were a -2y, you’d have to flip the inequality sign when dividing by that negative 2.

:)
jeyben [28]3 years ago
7 0

Answer:  The required slope-intercept form is y\leq 3x+21..

Step-by-step explanation:  We are given to write the following inequality in slope-intercept form :

-6x+2y\leq 42~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

the slope-intercept form of an inequality of the given form is as follows :

y\leq mx+c, where m is the slope and c is the y-intercept.

From inequality (i), we have

-6x+2y\leq 42\\\\\Rightarrow 2y\leq6x+42\\\\\Rightarrow y\leq\dfrac{6}{2}x+\dfrac{42}{2}\\\\\Rightarrow y\leq 3x+21.

Thus, the required slope-intercept form is y\leq 3x+21..

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11p + 2(p + 3) and 1 + p(13) + 2
Zarrin [17]
Answer:
1) 13p+6
2) 13p+3
6 0
3 years ago
3 (x-5) =5<br> what is x?
azamat

Answer: 20/3

So when solving this equation first distribute our 3,we will now have   3x-15=5.

Next we will Add 15 to both sides of our equation. Now we have 3x=20.Then divide our terms,and you will have 3x/3 = 20/3

<u>This will leave you with  1x=20/3. </u>

So the X is 20/3.

      Hope that helped!

8 0
3 years ago
william is thinking of two numbers both numbers are square numbers greater than 1 the sum of numbers is 100 write down two numbe
zheka24 [161]

Answer:

Step-by-step explanation:

At first,

Let start writing the squares of number 0 to 10,

0²=0

1²=1

2²=4

3²=9

4²=16

5²=25

6²=36

7²=49

8²=64

9²=81

10²=100

Now,

According to your question,

  1. The two numbers should be square numbers
  2. They should be greater than 1.
  3. Their sum should be 100.

Hence, your given conditions matches with the numbers 64 and 36.

Therefore, the numbers are 64 and 36.

  • 64 and 36 are greater than 1.
  • 64 is a square of 8 and 36 is the square of 6.
  • 64+36=100
3 0
3 years ago
Solve by the substitution method<br> 6x+5y =-26<br> -9x+y= 56
lozanna [386]

Answer:

I think its well point form is  (- 31/6, 19/2)

and equation form is x= - 31/6, y= 19/2

Step-by-step explanation:

Hope it helps!!!

4 0
3 years ago
Figure ABCDE has vertices a(-3, 3), b(2, 3), c(5, -2), d(0, -3), and e(-3, -2). Plot the points on your own coordinates grid and
Ilya [14]
<h2>Answer:</h2>

Shown below

<h2>Step-by-step explanation:</h2>

First of all, we have the following points:

a(-3, 3) \\ \\ b(2, 3) \\ \\ c(5, -2) \\ \\ d(0, -3) \\ \\ e(-3, -2)

To plot these points, we need to graph a coordinate grid. Recall that a coordinate grid is composed of two perpendicular lines, that we call the axes and are labeled like number lines. The horizontal axis is called the x-axis while the vertical axis is called the y-axis, and these two axes intersect at a point called the origin. Next, let's plot each point as follows:

<h2>PART 1. Plot the points on your own coordinates grid and connect in alphabetical order. </h2><h2></h2>

Point a:

Let's stand at the origin and then move three units to the left and three units up. The resulting point is shown in the firs figure below.

Point b:

Let's stand at the origin and then move two units to the right and three units up. The resulting point is shown in the firs figure below.

Point c:

Let's stand at the origin and then move five units to the right and two units down. The resulting point is shown in the firs figure below.

Point d:

Let's stand at the origin and then move three units to down. The resulting point is shown in the firs figure below.

Point e:

Let's stand at the origin and then move three units to the left and two units down. The resulting point is shown in the firs figure below.

Next, let's connect connect the points in alphabetical order, so that the line are connected from a to b, from b to c, from c to d, from d to e and from e to a again. So the resulting graph is shown in the second figure. As you can see, this is an irregular pentagon.

<h2>PART 2. Decompose figure ABCDE into rectangles and triangles.</h2>

Every pentagon can be divided up into three triangles. Hence, from the third figure. the triangles are:

ΔABE

ΔBDE

ΔBCD

Since a rectangle is a quadrilateral whose angles are all right angles, then there is no chance to obtain a rectangle from ABCDE. To obtain a rectangle, we'd need other points and this is not what the problem asks.

5 0
3 years ago
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