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4 years ago

Simulation ionic and covalent bonding

1 answer:

6 0

ionic bonds- atoms must ionize to bond and are metal/nonmetal
covalent- atoms do not need to ionize but can be polar or nonpolar to stay together since it doesn’t ionize and are nonmetal/nonmetal

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what are the three current biggest sources of electrical energy? i need to select three choices A. nuclear powerB. hydroelectric

tigry1 [53]

All of them are the current biggest sources of electrical energy.

3 of them will be explained.

------------------------

1) Natural gas:

it was the largest source, 38 % approx., of the USA electricity generation. It is used in steam turbines and gas turbines to generate electricity.

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2) Nuclear energy:

It was the source of 19% of the U.S. electricity generation in 2021. Nuclear power plants use steam turbines to produce electricity from fission.

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3) Coal power:

It was the 2nd.-largest energy source for US electricity generation in 2021.

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1 year ago

Where is this earthquake's epicenter?

ANTONII [103]

The answer is <span>Beijing, China</span>

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3 years ago

Read 2 more answers

What is the kinetic energy of a 25 kg object moving at a velocity of 2.5 m/s?

vovangra [49]

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k = \frac{1}{2} m {v}^{2} \\$

m is the mass

v is the velocity

From the question we have

$k = \frac{1}{2} \times 25 \times {2.5}^{2} \\ = 12.5 \times 6.25 \\ = 78.125 \: \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

6 0

3 years ago

how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?

defon

Answer:

<u>= 14.24g of </u> $(NH4)_{2}CO_{3}$ <u> is required.</u>

Explanation:

Reaction equation:

$(NH4)_{2}CO_{3}$ → $2NH_{3} + CO_{2} + H_{2} O$

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of $(NH4)_{2}CO_{3}$ - 96.09 g

0.148 mol of $(NH4)_{2}CO_{3}$ -- ?? g

=0.148 × 96.09

<u>= 14.24g of </u> $(NH4)_{2}CO_{3}$ <u> is required.</u>

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3 years ago

ASAP (2 questions & are iv the pic ) will get BRAINIEST

Zinaida [17]

Answer:

Hey again!

Q1: 4 N

Q2: 24 N

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3 years ago