All categories

3 years ago

_265Hs--->_16O+_9Be=_____?

Chemistry

1 answer:

madam [21]3 years ago

5 0

Answer:

265hs+24.464536b+16o

Explanation:

265hs+16o+9b(2.718282)

=265hs+16o+24.464536b

=265hs+24.464536b+16o

You might be interested in

A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

tatyana61 [14]

Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

First we have to calculate the moles of $CO_2$ and $N_2$ .

$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

$\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole$

Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

3 0

3 years ago

what mass of carbon dioxide will be produced when 12.9 g of butane reacts with an excess of oxygen in the following reaction?

Nadya [2.5K]

39.1 gCO2
I think if that’s an option

3 0

3 years ago

What areas of the work force can science be applied to?

Scorpion4ik [409]

Well definitely a scientist

4 0

4 years ago

A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each so

jeka94

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ = concentration of ist disinfectant solution = 16 %

$V_1$ = volume of pure acid solution = x gallons

$C_2$ = concentration of another disinfectant solution= 23%

$V_2$ = volume of another acid solution= (28-x) gallons

$C_3$ = concentration of resulting disinfectant solution = 18 %

$V_1$ = volume of resulting acid solution = 28 gallons

$16\times x+23\times (28-x)=18\times 28$

$x=20galllons$

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

7 0

3 years ago

What is the chemical formula of the salt produced by the neutralization of potassium hydroxide with sulfuric acid?

Novay_Z [31]

Hi my friend,
the salt produced is K2SO4
hope it helps.☺

4 0

3 years ago