Answer:
b
Explanation:
stable climate will mean there is one climate and we will have the same animals and plants everywere
This reaction would produce salt and water- Sodium Sulphate and Water.
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Answer:
![[H_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.183M)
![[I_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.183M)
![[HI]_{eq}=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.025M)
Explanation:
Hello.
In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:
Whereas the law of mass action (equilibrium expression) is:
![Kc=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
That in terms of initial concentrations and reaction extent or change 
turns out:
![Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7Bx%2Ax%7D%7B%28%5BHI%5D_0-2x%29%5E2%7D%5C%5C%5C%5C54.3%3D%5Cfrac%7Bx%5E2%7D%7B%280.391M-2x%29%5E2%7D)
And the solution via solver or quadratic equation is:
Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:
![[HI]_{eq}=0.391M-2*0.183M=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.391M-2%2A0.183M%3D0.025M)
Regards.
Answer:
<em><u>Proton number of the supposed discovery debunked the theory.</u></em>
Explanation:
Proton number of an element is also its atomic number.
For the element in question to have had a proton number that wasn't 119, it could not have been a new element.
Furthermore, the characteristics described (proton number especially) describe exactly the Germanium element.
I believe this was helpful.
Answer:
HF is the acid
Explanation:
The Brønsted-Lowry theory defines the acids and bases in chemistry as follows:
An acid is the species that can donate a proton
A base can accept protons.
In the reaction:
HF(aq) + NH₃(aq) → NH₄⁺(aq) + F⁻(aq)
As you can see, HF can donate its proton to produce F⁻: HF is the acid
<em>In the same way, NH₃ is accepting a proton, NH₃ is the base.</em>
