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postnew [5]
3 years ago
10

I need the answer in fast

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

I think it is letter C.

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Solve for y 2x-5y=10
scZoUnD [109]

Answer:

y = 2/5x - 2

Step-by-step explanation:

Step 1: Write equation

2x - 5y = 10

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -5y = 10 - 2x
  2. Divide both sides by -5: y = -2 + 2/5x
  3. Rewrite: y = 2/5x - 2
6 0
3 years ago
Read 2 more answers
Mae Ling earns a weekly salary of $315 plus a 6.0% commission on sales at a gift shop. How much would she make in a work week if
Radda [10]

Answer:

$561

Step-by-step explanation:

4100 x0,06=  246

246+315=561

4 0
3 years ago
For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm
Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

(\frac{14 \ mm}{7 \ mm})^{2}

= \frac{196 \ mm^{2} }{49\ mm^{2} }

=\frac{4}{1}

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0
2 years ago
Amanda needs to make a garden plot which has an area less than 18 sq. feet. The length should be 3 feet longer than the width. W
SCORPION-xisa [38]

Answer:

<em>Any width less than 3 feet</em>

Step-by-step explanation:

<u>Inequalities</u>

The garden plot will have an area of less than 18 square feet. If L is the length of the garden plot and W is the width, the area is calculated by:

A = L.W

The first condition can be written as follows:

LW < 18

The length should be 3 feet longer than the width, thus:

L = W + 3

Substituting in the inequality:

(W + 3)W < 18

Operating and rearranging:

W^2 + 3W - 18 < 0

Factoring:

(W-3)(W+6)<0

Since W must be positive, the only restriction comes from:

W - 3 < 0

Or, equivalently:

W < 3

Since:

L = W + 3

W = L - 3

This means:

L - 3 < 3

L < 6

The width should be less than 3 feet and therefore the length will be less than 6 feet.

If the measures are whole numbers, the possible dimensions of the garden plot are:

W = 1 ft, L = 4 ft

W = 2 ft, L = 5 ft

Another solution would be (for non-integer numbers):

W = 2.5 ft, L = 5.5 ft

There are infinitely many possible combinations for W and L as real numbers.

6 0
3 years ago
How many extraneous solutions exist for the logarithmic equation below if it is solved in the most efficient way possible?log_(2
Nadusha1986 [10]

Answer:

No extraneous solution

Step-by-step explanation:

We have the logarithmic equation given by,

\log_{2}[\log_{2}(\sqrt{4x})]=1

i.e. \log_{2}(\sqrt{4x})=2^{1}

i.e. \sqrt{4x}=2^{2}

i.e. \sqrt{4x}=4

i.e. 4x=4^{2}

i.e. 4x=16

i.e. x=4

So, the solution of the given equation is x=4.

Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is ( 0,\infty ).

Therefore, the domain of the given function is x > 0.

We know that the extraneous solution is the solution which does  not belong to the domain.

But as x=4 belongs to the domain x > 0.

Thus, x = 4 is not an extraneous solution.

Hence, this equation does not have any extraneous solution.

7 0
3 years ago
Read 2 more answers
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