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ra1l [238]
1 year ago
15

How many bars would the team need to purchase from

Mathematics
1 answer:
Anna007 [38]1 year ago
5 0

The numbers of bars that the team have to get from each company in order for the total cost to be equal is 40.

<h3>What is the purchase about?</h3>

Since n = numbers of bars purchase.

y= total cost in dollars

Company A = 0.75n

Company B = 10 + 0.50n

Therefore, to find the numbers of bars that the team would need to purchase from each company in order for the total cost to be equal =

0.75n = 10 + 0.50n

0.2n = 10

n = 40

Learn more about purchase from

brainly.com/question/5168855

#SPJ1

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The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c
Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle.  We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}

\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01

3 0
3 years ago
2x-1/3x+1=6x-1/9x-3​
shtirl [24]
The answer is x=3

So c is 3
6 0
3 years ago
I dont understand how to do this, looking for someone who can help
earnstyle [38]
The answer should be a segment. have a great day :)))
8 0
3 years ago
F (x)=5x+1 9(x)=-2x+15
german

Answer:

x = 0

Step-by-step explanation:

(x)=5x+19(x)=-2x+15

We move all terms to the left:

(x)-(5x+19(x))=0

We add all the numbers together, and all the variables

x-(+24x)=0

We get rid of parentheses

x-24x=0

We add all the numbers together, and all the variables

-23x=0

x=0/-23

x=0

4 0
3 years ago
30 POINTS AVAILABLE
kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

3 0
3 years ago
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