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antiseptic1488 [7]
4 years ago
15

A 1500 kg car travelling at 25 m/s collides with a 2500 kg van which had

Physics
1 answer:
sertanlavr [38]4 years ago
6 0
I’m not sure I think if you google it it should pop up or go on quizlet sorry
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imagine that you are on a spaceship that is far from the sun or any planet. Explain why a 500 kg piece of equipment would be dif
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Even though the object is weightless, it would need inertia, I.e, you pushing it or any form of transportation. So you would still have to push that 500kg to just keep it moving in space. Say if it were a planet with less gravitational force, it would be weightless.

8 0
3 years ago
Considering , will F ever equal zero?
Kamila [148]
No it will not because F will equal 3 not 0

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4 years ago
Read 2 more answers
180 cm3 of hot tea at 97 °C are poured into a very thin paper cup with 20 g of crushed ice at 0 °C. Calculate the final temperat
Zolol [24]

Answer : The final temperature of the mixture is 91.9^oC

Explanation :

First we have to calculate the mass of water.

Mass = Density × Volume

Density of water = 1.00 g/mL

Mass = 1.00 g/mL × 180 cm³ = 180 g

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of hot water (liquid) = 4.18J/g^oC

c_2 = specific heat of ice (solid)= 2.10J/g^oC

m_1 = mass of hot water = 180 g

m_2 = mass of ice = 20 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of hot water = 97^oC

T_2 = initial temperature of ice = 0^oC

Now put all the given values in the above formula, we get

(180g)\times (4.18J/g^oC)\times (T_f-97)^oC=-(20g)\times 2.10J/g^oC\times (T_f-0)^oC

T_f=91.9^oC

Therefore, the final temperature of the mixture is 91.9^oC

8 0
3 years ago
A motorcycle is travelling north at 11m/s. How much time would it take for the motorcycle to increase its velocity to 26m/s (N)
DaniilM [7]
Using the kinematic equation,
v = u + at
26 = 11 + 3t
15 = 3t
t = 5 seconds.
Time required is 5 seconds.
8 0
3 years ago
For this position-time graph, what is the average velocity for the entire curve?
Vinil7 [7]
A. Without doing much math, it can be seen from the graph that the altitude is decreasing. The slope of the position time graph determines velocity, so by comparing the start to the end of the graph, it can be seen that -100m was the change in altitude and 25 seconds was the change in time. Divide -100 by 25 to get -4m/s.
7 0
4 years ago
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