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3 years ago

How does the role of blood protect the body

Physics

1 answer:

maksim [4K]3 years ago

4 0

Well it transports white blood cells to infected areas.

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After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

loris [4]

Answer:

0.4455 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

$m=62\times 25+15\times 3+5\times 3+25\\\Rightarrow m=1635\ kg$

Here the spring constant is not given so let us assume it as $k=36000\ N/m$

Here, the forces are balanced

$mg=kx\\\Rightarrow 1635\times 9.81=36000\times x\\\Rightarrow x=\dfrac{1635\times 9.81}{36000}\\\Rightarrow x=0.4455\ m$

The springs are compressed by 0.4455 m

3 0

3 years ago

What are two ways thermal energy can be increased in a system?

MaRussiya [10]

Adding thermal energy
Performing work on the system

3 0

3 years ago

which of the following examples illustrates an energy transfer between the atmosphere and hydrosphere

Elan Coil [88]

Answer: polar ice reflecting the Sun's light back toward space

6 0

4 years ago

Read 2 more answers

Two skiers start at the same place at the top of the hill, and finish at the same place at the bottom. Skier A takes a straight,

Rus_ich [418]

Answer:A

Explanation:

Given

Skier A takes straight, smooth route while Skier B takes curvy, bumpy route to finish.

We know gravity is conservative in nature i.e. work done against it is independent of path followed

So work done by gravity for A and B is same

According to Work energy Theorem Change in the kinetic Energy is equal to work done by all the forces.

$W_g=\frac{1}{2}mv^2$

$W_g=mgh$

where h=vertical height of hill

thus $v=\sqrt{2gh}$

which is same for both A and B

6 0

3 years ago

A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8

Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

$\eta =1-\frac{T_c}{T_h}$

where,

$\eta$ = efficiency = 0.780

$T_h$ = Temperature of hot reservoir = ?

$T_c$ = Temperature of cold reservoir = $-24.8^oC=273+(-24.8)=248.2K$

Now put all the given values in the above expression, we get:

$\eta =1-\frac{T_c}{T_h}$

$0.780=1-\frac{248.2K}{T_h}$

$T_h=1128.18K$

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0

3 years ago