Someone please help me with this I’m struggling

If the statement if it cold then i wear a jacket is assumed to be true is it converse if i wear a jacket it must be cold also al

Archy [21]

The converse of any statement, true or false, is never always true. The only guaranteed true statement is a contrapositive of a true statement. A contrapositive is a statement where the hypothesis and conclusion are switched, and both sides are negated.

Final Answer: no

3 0

3 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$

8 0

3 years ago

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How do I solve this finding the first four of the sequence?

irga5000 [103]

Answer:

Step-by-step explanation:

a(1) = -7 (given)

a(2) = a(1) + 4 = -7 + 4 = -3

a(3) = a(2) + 4 = -3 + 4 = 1

a(4) = a(3) + 4 = 1 + 4 = 5

and so on.

4 0

3 years ago

Read 2 more answers

Which function has the greatest rate of change on the interval from x = 3 pi over 2 to x = 2π?

vodka [1.7K]

The average rate of change for the function f(x) can be calculated from the following equation
$\frac{f( x_{2})-f( x_{1} )}{ x_{2} - x_{1} }$

By applying the last formula on the given equations
(1) the first function f
from the table f(3π/2) = -2 and f(2π) = 0
∴ The average rate of f = $\frac{f(2 \pi)-f( \frac{3 \pi}{2} )}{2 \pi - \frac{3 \pi}{2} } = \frac{0-(-2)}{ \frac{\pi}{2} }= \frac{2}{ \frac{\pi}{2} } = \frac{4}{\pi}$

(2) the second function g(x)
from the graph g(3π/2) = -2 and g(2π) = 0
∴ The average rate of g = $\frac{g(2 \pi)-g( \frac{3 \pi}{2} )}{2 
\pi - \frac{3 \pi}{2} } = \frac{0-(-2)}{ \frac{\pi}{2} }= \frac{2}{ 
\frac{\pi}{2} } = \frac{4}{\pi}$

(3) the third function h(x) = 6 sin x +1
∴ h(3π/2) = 6 sin (3π/2) + 1 = 6 *(-1) + 1 = -5
 h(2π) = 6 sin (2π) + 1 = 6 * 0 + 1 = 1
∴ The average rate of h = $\frac{f(2 \pi)-f( \frac{3 \pi}{2} )}{2 
\pi - \frac{3 \pi}{2} } = \frac{1-(-5)}{ \frac{\pi}{2} }= \frac{6}{ 
\frac{\pi}{2} } = \frac{12}{\pi}$

By comparing the results, The function which has the greatest rate of change is h(x)


So, the correct answer is option C) h(x)

4 0

3 years ago

Kayla won 64 lollipops playing horseshoes at the county fair. At school she gave four every student in her math class. She only

GuDViN [60]

14 students if she gives four lollipops to every student and has 8 left.

6 0

3 years ago