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nexus9112 [7]
3 years ago
9

Solve using quadratic formula. 2x^2+6x+3=0

Mathematics
1 answer:
guapka [62]3 years ago
4 0
x = \frac{-b +/-  \sqrt{b^{2} -4ac} }{2a}

a = 2
b = 6
c = 3

x = \frac{-6 +/- \sqrt{6^{2} -4*2*3} }{2*2}

x = 0.634 or x = -2.366
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