Question

Solve using quadratic formula. 2x^2+6x+3=0

Answer 1

$x = \frac{-b +/- \sqrt{b^{2} -4ac} }{2a}$

a = 2
b = 6
c = 3

$x = \frac{-6 +/- \sqrt{6^{2} -4*2*3} }{2*2}$

$x = 0.634$ or $x = -2.366$