X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
Answer:
y = (6/5) - (7/5) x
Step-by-step explanation:
goal: to rearrange the equation such that it takes the form:
y = f(x) ; where f(x) is an expression in terms of x
Given:
7x+5y=6 subtract 7x from both sides
5y = 6 - 7x (divide both sides by 5)
y = (6-7x) / 5
y = (6/5) - (7/5) x
Answer:
f(2) = 3
Step-by-step explanation:
We are given:
f(0) = 3
and
f(n+1) = -f(n) + 5
We have to find the value of f(2). In order to find f(2) we first have to find f(1)
f(n + 1) = - f(n) + 5
Using n = 0, we get:
f(0 + 1) = - f(0) + 5
f(1) = -f(0) + 5 Using the value of f(0), we get
f(1) = -3 + 5 = 2
Now using n = 1 in the function, we get:
f(1 + 1) = - f(1) + 5 Using the value of f(1), we get
f(2) = -2+ 5
f(2) = 3
Thus the value of f(2) will be 3
