Answer:
the answer is
<em>n</em><em>=</em><em>5</em>
SANA MAKATULONG
<em>AND</em><em> </em><em>PLS</em><em> </em><em>FOLLOW</em>
Answer:
63.59
Step-by-step explanation:
If the perimeter is 32.13, that means it is equal to
2r + 2πr/4 = 32.13
Solving this for r we get 9
Now, we can find the area, which is 3.14*r^2 / 4. Assuming pi to be 3.14 again, we get 63.585. Rounding this to the nearest hundredth, we get 63.59
Answer: L = 29cm
Step-by-step explanation:
Let's go!!
To find any rectangle area, you have to apply this formula: A = L . w , where L is the length and w is the width.
So, we have w = L - 13 (the width is 13 less than the Length) and then, perimeter is 90 cm.
Well, I hope you remember that the perimeter of rectangle is 2L + 2W. In this case, 2L + 2w = 90
Then, you might to solve this system of equation:
2L + 2w = 90
w = L - 13
Simplifying the first equation, you'll have L + w = 45 (you can divide everything of 2).
Our new system:
L + w = 45
w = L - 13
Using the substituition method:
L + L - 13 = 45
2L = 58
L = 29 cm
the width is 29 - 13 = 16 cm
So,first step is to write ![(fog)(-4)) =f[g(-4)] \\](https://tex.z-dn.net/?f=%20%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%5C%5C%20)
Now we start from inner paranthesis
,we need to first find value of
![g(-4) =\frac{\sqrt{12-(-4)}}{3}\\ =\frac{\sqrt{12+4}}{3}\\ =\frac{\sqrt{16}}{3}\\ =\frac{4}{3}\\ (fog)(-4)) =f[g(-4)] =f(\frac{4}{3}) =9(4/3)^{2} =9*(16/9) =144/9 =16](https://tex.z-dn.net/?f=%20g%28-4%29%20%3D%5Cfrac%7B%5Csqrt%7B12-%28-4%29%7D%7D%7B3%7D%5C%5C%20%3D%5Cfrac%7B%5Csqrt%7B12%2B4%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B%5Csqrt%7B16%7D%7D%7B3%7D%5C%5C%0A%3D%5Cfrac%7B4%7D%7B3%7D%5C%5C%0A%28fog%29%28-4%29%29%20%3Df%5Bg%28-4%29%5D%20%3Df%28%5Cfrac%7B4%7D%7B3%7D%29%20%3D9%284%2F3%29%5E%7B2%7D%20%3D9%2A%2816%2F9%29%20%3D144%2F9%20%3D16%20)
