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Stells [14]
4 years ago
6

Evaluate 3^2 + (6 − 2) ⋅ 4 − 6/3 a. 20 b. 23 c. 50 d. 26

Mathematics
2 answers:
Sergeeva-Olga [200]4 years ago
4 0
I hope this helps you

Aliun [14]4 years ago
4 0
Hi there!

Okay so remember PEMDAS. Also you could use a calculator for this but you can also use pencil and paper. Anyway, steps are below:

3²+(6-2)(4)-6/3

= 9+(6-2)(4)-6/3
= 9+(4)(4)-6/3
= 9+16-6/3
= 25-6/3
= 25-2
= 23

Your final answer is B, 23.

Hope this helped!

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samuel and jason spend 3/4 of their combined earnings from wednesday to buy a gift. Together they earned $21.88 how much did the
tiny-mole [99]
3/4 of their combined earnings should be $16.41
3 0
3 years ago
Read 2 more answers
Calculate this reflection of the triangle:
Mice21 [21]

Answer:

a = 3, b = 0, c = 0, d = -2

Step-by-step explanation:

<em>To find the reflection Multiply the matrices</em>

∵ The dimension of the first matrix is 2 × 2

∵ The dimension of the second matrix is 2 × 3

<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>

2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix

\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]  × \left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]  = \left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]

Compare the elements in the answer with the third matrix to find the values of a, b, c, and d

∴ a = 3

∴ b = 0

∴ c = 0

∴ d = -2

7 0
4 years ago
Which equation shows<br><br> equation shows y = - 3x +4<br><br> x + 4 is in standard form?
svet-max [94.6K]

Answer:

7x-y=-4

Step-by-step explanation:

Let me know if this right please :(

Hope it was is helpful for you :)

3 0
3 years ago
What is the domain of the function?<br> x + 3<br> f(x) =<br> VX + 3
ahrayia [7]

Your question is a little ambiguous, but I am assuming that you meant to say the function f(x) = x+3

Thus, I am solving your question based on assuming the function such as

f(x)=x+3

But, it would still clear your concept, no matter what the function is.

Answer:

we conclude that

\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The graph is also attached.

Step-by-step explanation:

Given the function

f(x)=x+3

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

As the function has no undefined points nor domain constraints.

Thus, the domain is

-\infty \:

Therefore, we conclude that

\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The graph is also attached.

3 0
3 years ago
Jose bought 3 pens and 6 pencils for $6.60. Amy bought 5 pens and 8 pencils for $10.00. How much does one pencil cost?
xenn [34]

Answer:

pen = $1.20,  pencil = $0.50

Step-by-step explanation:

let x = pen

let y = pencil

create system of equations:

3x + 6y = 6.60        [can be simplified to be x + 2y = 2.20]

5x + 8y = 10.00

substitution method:

x = 2.2 - 2y

5(2.2 - 2y) + 8y = 10

11 - 10y + 8y = 10

-2y = -1

y = 1/2

solve for 'x':

3x + 6(1/2) = 6.6

3x + 3 = 6.6

3x = 3.6

x = 1.2

7 0
3 years ago
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