D. 52 km/h
relatve to the track outside. Galiliean relativity
When the distance is decreasing, the frequency of the received wave form will be higher than the source wave form. the sound changes because, the sound waves and their frequency changes as they pass by you as they are moving in the same direction. HOPE THIS HELPED YOU :)
Answer:
Impulse, J = 4.14 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = -28 m/s (it is assumed that the initial direction of the ball is in the -x direction)
Final speed of the ball, v = 41 m/s
It can be assumed to find the impulse delivered to the ball by the racket. The impulse delivered is equal to the change in momentum of the object. Mathematically, it is given by :
J = 4.14 kg-m/s
So, the impulse delivered by the ball to the racket is 4.14 kg-m/s. Hence, this is the required solution.
Answer: frequency = 523.2 Hz
Explanation:
One octave higher = 2f of the last octave.
For instance, if C2 = 4 Hz
A octave higher will be C3 in which its frequency will be 2 × 4Hz = 8Hz
Back to the question.
One octave higher frequency will therefore equal to:
2f = 2 × 261.6 = 523.2 Hz
That would be the velocity ... speed and direction ... of
the launch out of the cannon.