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irina1246 [14]
2 years ago
10

A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

Physics
2 answers:
jekas [21]2 years ago
7 0

A reference point would be something not on the ship which could be used to calculate distance traveled.

Answer: C.) A lighthouse on a nearby Island

Alexxx [7]2 years ago
5 0

Answer:

C.) A lighthouse on a nearby Island

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You have to travel 5000 meters. You only have two minutes (120 seconds) to get there. How fast must you travel to get there in t
Sholpan [36]

Answer:

416.667 m/s

Explanation:

divide the distance by the time

8 0
3 years ago
Which of the following is a scientific law?
Varvara68 [4.7K]

Answer:

B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.

Explanation:

The rest are societal laws, as they are telling you something you should avoid or follow.

Hope this helps :)

7 0
3 years ago
Read 2 more answers
Cual es la rapidez media de un guepardo que recorre 100 metros en 4 segundos? ¿Y si recorre 50 m en 2 s?
Maru [420]

Answer:

La rapidez media es 25 m/s en ambos casos.

Explanation:

Podemos definir como rapidez media al cociente entre la distancia total recorrida y el tiempo que se tardó en recorrer dicha distancia.

Así tenemos:

Rapidez media = Distancia/tiempo.

Entonces si el guepardo recorre 100m en 4 segundos, su rapidez media es:

Rapidez media = 100m/4s = 25 m/s

En el caso de que el guepardo recorre 50 metros en 2 segundos, su rapidez media será:

rapidez media = 50m/2s = 25m/s

Es el mismo resultado, pues recorrió la mitad de distancia en la mitad de tiempo.

4 0
3 years ago
a crowbar of 2 meter is used to lift an object of 800N if the effort arm is 160cm , calculste the effort applied
Vitek1552 [10]

Answer:

200 N

Explanation:

The crowbar is 2 meter, or 200 cm.  The effort arm is 160 cm, so the moment arm of the object is 40 cm.

(800 N) (40 cm) = F (160 cm)

F = 200 N

5 0
3 years ago
A 0.43-kg object mass attached to a spring whose spring constant is 561 N/m executes simple harmonic motion. If its maximum spee
VLD [36.1K]

Answer:

0.22 m

Explanation:

m = 0.43 kg, K = 561 N/m

Vmax = 8 m/s

Let the amplitude of the oscillations be A.

The formula for the angular frequency of oscillation sis given by

\omega  = \sqrt{\frac{K}{m}}

\omega  = \sqrt{\frac{561}{0.43}}

ω = 36.1 rad/s

The formula for the maximum velocity is given by

Vmax = ω x A

A = Vmax / ω

A = 8 / 36.1 = 0.22 m

4 0
3 years ago
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