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klio [65]
3 years ago
15

4 bananas and 3 peaches cost $10. We can represent this information as 4x +3y = $10. The x represents the cost of bananas and th

e y represents the cost of peaches.
a) Find an equation for 1 banana and 2 peaches cost $5

b) With the two equations, use a matrix method on your calculator to determine the cost of a banana and the cost of a peach.
Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

a  x+2y =5

b  x=1  y=2

Step-by-step explanation:

4x+3y = 10

So the cost of 1 banana is x and the cost of 1 peach is y

a) we want the cost of 1 banana and 2 peaches

1x+2y

That is equal to 5 dollars

1x+2y =5

x+2y =5

b

The matrixes are

1   2         x              5

         *           =

4   3          y            10

Using my calculator, x=1  y=2

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Answer:

y = 9

Step-by-step explanation:

We notice that both points have a y-coordinate of 9. Since they are the same, the equation must be y = 9 because the function can't "dip" or "rise", otherwise it would be a piecewise function and not a linear function. The equation y = 9 basically means that no matter what x is, y will always be 9.

7 0
3 years ago
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QUESTION in the diagram below the following are rectangles. ACEG ;BCDJ ; JDEF and HJFG is a square AB =AH = x ;BC=5 ; HG=3 Area
White raven [17]

The area of the rectangle ACEG is the amount of space on it, and the area of square HJFG is 9 square units

<h3>How to determine the area of the figures?</h3>

The area of a rectangle is:

Area = Length * Width

The area of a square is:

Area = Length * Length

From the question, the given parameters are:

AB =AH = x ;

BC=5;

HG=3

This means that the area of square HJFG is:

Area = HG * HG

Area = 3 * 3

Area = 9

<em>Note that the other areas cannot be calculated because the question is incomplete</em>

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7 0
2 years ago
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aleksandrvk [35]
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7 0
4 years ago
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The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
3 years ago
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