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klio [65]
3 years ago
15

4 bananas and 3 peaches cost $10. We can represent this information as 4x +3y = $10. The x represents the cost of bananas and th

e y represents the cost of peaches.
a) Find an equation for 1 banana and 2 peaches cost $5

b) With the two equations, use a matrix method on your calculator to determine the cost of a banana and the cost of a peach.
Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

a  x+2y =5

b  x=1  y=2

Step-by-step explanation:

4x+3y = 10

So the cost of 1 banana is x and the cost of 1 peach is y

a) we want the cost of 1 banana and 2 peaches

1x+2y

That is equal to 5 dollars

1x+2y =5

x+2y =5

b

The matrixes are

1   2         x              5

         *           =

4   3          y            10

Using my calculator, x=1  y=2

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Vsevolod [243]

Answer:

\dfrac{-1}{6}

Step-by-step explanation:

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Step 2: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the function

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ sin(x)-tan(x)]}{\frac{d}{dx} (x^3)}\\= \lim_{ x\to \ 0} \dfrac{cos(x)-sec^2(x)}{3x^2}\\

Step 3: substitute x = 0 into the resulting function

= \dfrac{cos(0)-sec^2(0)}{3(0)^2}\\= \frac{1-1}{0}\\= \frac{0}{0} (ind)

Step 4: Apply  L'Hôpital's rule, by differentiating the numerator and denominator of the resulting function in step 2

= \lim_{ x\to \ 0} \dfrac{\frac{d}{dx}[ cos(x)-sec^2(x)]}{\frac{d}{dx} (3x^2)}\\= \lim_{ x\to \ 0} \dfrac{-sin(x)-2sec^2(x)tan(x)}{6x}\\

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Step 7: substitute x = 0 into the resulting function in step 6

=  \dfrac{[ -cos(0)-2(sec^4(0)+2sec^2(0)tan^2(0)]}{6}\\\\= \dfrac{-1-2(0)}{6} \\= \dfrac{-1}{6}

<em>Hence the limit of the function </em>\lim_{ x\to \ 0} \dfrac{sin(x)-tan(x)}{x^3} \  is \ \dfrac{-1}{6}.

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