Answer:-
(a) 3.5
(b) 3
Explanation:-
2KClO3 --> 2KCl + 3 O2
From the equation we see that 2 moles of KClO3 gives 2 moles of KCl.
So 3.5 moles of KClO3 will give 3 moles of KCl.
Again
3 moles of O2 are produced with 2 moles of KCl.
If 4.5 moles of O2 produced then
moles of KCl = 4.5 x 2/3
=3
This is an incomplete question, here is a complete question.
Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.
CaCO₃, Ksp = 8.7 × 10⁻⁹
Answer : The solubility of CaCO₃ is, 
Explanation :
As we know that CaCO₃ dissociates to give 
ion and 
ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ca^{2+}][CO_3^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BCO_3%5E%7B2-%7D%5D)
Let solubility of CaCO₃ be, 's'
Therefore, the solubility of CaCO₃ is,
Answer:
half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive ...
Explanation:
braniest
The answer is A i think if it’s wrong someone correct me
It well be 9025 because it will dissolve in 0.8 hcl soluiton
