Answer:
In first shell duplet rule is applied because first shell contains maximum 2 electrons
Explanation:
Answer:
The density of the block is 2.827 grams/ cubic inch
Explanation:
The density of the block can be obtained by dividing the given mass of the block by its volume.
Density = mass / volume
The mass of the block given is 435.5 grams
The volume of the block can be obtained by using the formula:
Volume = Length X breadth X height
Volume = 3.5 X 8 X 5.5 = 154 
There fore the density will be 435.5 / 154 = 2.827 grams/ cubic inch
The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.
<h3>What is a neutralization reaction?</h3>
It is a reaction involving an acid and a base to produce salt and water.
From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.
Thus, the neutralization reaction is represented by the equation:
More on neutralization reactions can be found here: brainly.com/question/20038776
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Answer:
When halogen elements react with group one metals they form halide salts.
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements can not be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.
When halogen elements react with group one metals they form halide salts.
Alkali metals have one valance electron and halogens needed one electron to complete the octet thus alkali metals loses one electron which is accepted by halogens atom and form ionic compound called halide salts.
For example:
2Na + Cl₂ → 2NaCl
2K + Cl₂ → 2KCl
2Rb + Cl₂ → 2RbCl
2Li + Cl₂ → 2LiCl
With bromine:
2Na + Br₂ → 2NaBr
2K + Br₂ → 2KBr
2Rb + Br₂ → 2RbBr
2Li + Br₂ → 2LiBr
With iodine:
2Na + I₂ → 2NaI
2K + I₂ → 2KBI
2Rb + I₂ → 2RbI
2Li + I₂ → 2LiI
The elements that compose it and the arrangement of its atoms.
