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4 years ago

A potassium iodide compound is represented by which formula?

Chemistry

2 answers:

andrew11 [14]4 years ago

7 0

It is represented by C) KI

K+
I-

So it's KI

Tanya [424]4 years ago

5 0

<h2>Answer : Option C) KI</h2><h3>Explanation :</h3>

A potassium iodide compound is represented as KI.

It has $K^{+}$ and $I^{-}$ in it.

The potassium (K) reacts with Iodine vapors (I) to form KI (Potassium iodide).

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5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a

max2010maxim [7]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.364g$

Mass of $H_2O=0.0596g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, $\frac{12}{44}\times 0.364=0.0993g$ of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, $\frac{2}{18}\times 0.0596=0.0067g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles$ ]

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = $\frac{0.00828}{0.0067}=1.23\approx 1$

For Hydrogen = $\frac{0.0067}{0.0067}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}$

The general formula of an alkane is $C_nH_{(2n+2)}$ , where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

7 0

4 years ago

How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?

andrezito [222]

109 particles in finite oven tetroxide

8 0

3 years ago

Ty for anyone helping!

sp2606 [1]

23. Enzyme A, as the temperature increases, the rate of reaction goes down. However, Enzyme B as the temperature goes up the reaction goes up.

24. Enzyme B is more active in a human cell, the reaction is what you want and everytime the temperature goes up in enzyme B the reaction goes up.

6 0

3 years ago

usando el concepto de valencia para los elementos S, P Y Br predice las formulas de los compuestos mas simples formados por esto

hram777 [196]

Explanation:

Teniendo en cuenta los numeros de oxidacion negativos de cada uno

P:fosforo(-3)

S:Azufre (-2)

Br:Bromo (-1)

Y el H: hidrogeno con una valencia

positiva de +1

los compuesto que se formaran son los siguientes

1 H3P= fosfuro de hidrogeno

2 H2S= sulfuro de hidrogeno

3 HBr= Acido bromhidrico

ESPERO ABERTE AYUDADO ;D

6 0

3 years ago

Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas

Zinaida [17]

Answer: Number of molecules of hydrogen gas $6.32\times 10^{32}$

Explanation:

$2Na+2H_2O\rightarrow 2NaOH+H_2$

Number of moles of sodium = $\frac{\text{mass of sodium}}{\text{molar mass of sodium}}=\frac{48.7 g}{23 g/mol}=2.11mol$

According to reaction , 2 moles of sodium produces 1 mole of hydrogen gas , then 2.11 mol of sodium will= $\frac{1}{2}\times 2.11 mol$ of hydrogen gas that is 1.05 moles of hydrogen gas.

Number of molecules = $N_A(\text{Avogadro number})\times$ moles of substance

Moles of hydrogen gas formed = 1.05 moles

Number of molecules of hydrogen gas = $N_A\times$ moles of hydrogen gas

Number of molecules of hydrogen gas $=6.022\times 10^{23} mole^{-1}\times 1.05 mole=6.32\times 10^{32}$

8 0

3 years ago