Answer:
305 g of CO₂
3.77 × 10⁵ kJ
Explanation:
Let's consider the global reaction for photosynthesis.
6 CO₂(g) + 6 H₂O(l) → C₆H₁₂O₆(g) + 6 O₂(g) ΔHrxn = 2802.8 kJ
<em>A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?</em>
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Let's consider the following relations:
- The potato is 100%-73%=27% glucose by mass.
- 1 lb = 453.59 g.
- 6 moles of CO₂ produce 1 mole of glucose.
- The molar mass of glucose is 180.156 g/mol.
- The molar mass of carbon dioxide is 44.01 g/mol.
Then, for a 1.70 lb potato:
<em>How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?</em>
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According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:
The elements are placed in specific places on the periodic table based on their atomic number and outer electronic configuration which gives them certain properties.
The elements of same groups have same number of valence electrons.
Group 1: one electron in valence shell
Group 2: two electrons in valence shell.
Helium has only two electrons in its outer shell and it is grouped with elements that have completely filled outer orbitals, noble gas.
Answer:
Covalent bonding occurs when atoms share valence electrons to form a chemical bond. Atoms of nonmetals form covalent bonds by sharing electrons in order to achieve an octet of valence electrons, like the noble gases, except for helium, which only has two valence electrons. The octet refers to the highest energy s and p sublevels, the valence shell, which in noble gases, except for helium, are filled with eight electrons, two in the s sublevel and six in the p sublevel.
I think you have the first three right
The last one should be increase, if there’s more reactants the particles are more likely to collide so the rate of reaction would increase, let me know if you want me to try explain that in an easier way aha
