Answer: The correct option is, (B) 12.3 KJ
Solution :
First we have to calculate the moles of water.
Now we have to calculate the amount of heat released.
Formula used :
where,
q = heat released
n = number of moles = 2.04 mole
= molar enthalpy of fusion of a substance = -6.01 KJ/mole
Now put all the give values in the above formula, we get the amount of heat released.
The negative sign indicate heat released.
Therefore, the amount of heat released is, 12.3 KJ
Answer:
0.0342 moles
Explanation:
Moles and Mass are related as,
Moles = Mass / M.Mass
M.Mass of NaCl = 58.44 g/mol
Putting values,
Moles = 2.00 g / 58.44 g/mol
Moles = 0.0342 moles
The unit measurement of the rate constant is a guide to tell you the rate order. If it's unit is 1/time, then it is a first-order reaction. From the picture attached, the formula to be used would be:
ln[A] = ln[A₀] - kt
ln[0.21] = ln[A₀] - (1.37)(1.2)
Solving for A₀,
A₀= 1.09 M
<em>Hence, the original concentration of X was 1.09 M.</em>
Answer:
The answer to your question is 1.46 g of Cl₂
Explanation:
Data
mass of Cl₂ = ?
mass of NaCl = 2.4 g
Chemical reaction
2Na + Cl₂ ⇒ 2NaCl
Process
1.- Calculate the molar mass of chlorine and sodium chloride
Molar mass Cl₂ = 2 x 35.5 = 71 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g
2.- Use proportions to solve this problem
71g of Cl₂ --------------------- 2(58.5g) NaCl
x --------------------- 2.4 g
x = (2.4 x 71) / 2(58.5)
x = 170.4 / 117
x = 1.46 g of Cl
<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>
In general, the gas equation can be written
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)
T = temperature, Kelvin
n = N / No
n = mole
No = Avogadro number (6.02.10²³)
n = m / MW
m = mass
MW = molecular weight
For density , can be formulated :
P = 327 mmHg = 0,430263 atm
R = 0.082 L.atm / mol K
T = 48 ºC = 321.15 K
MW of H₂ = 2.015 g/mol
The density :