The pancreatic juice is secreted by the pancreas. This pancreatic juice is secreted into the first part of the small intestine known as the duodenum. This pancreatic juice is rich in various enzymes that help in the digestion of various food components (carbohydrates, fats, and proteins). Besides being rich in enzymes, it is also rich in bicarbonate content. The bicarbonate works to neutralize the acidic chyme. This helps the enzymes to function and carry out digestion properly. If the pancreas fails to produce bicarbonate, then the function of enzymes will be altered, and the acidic chyme (coming from the stomach) will damage the small intestine walls.
To perform this test to check if gold is real, make a light, tiny scratch on the item using a small nail file. Choose a spot that is not noticeable if possible. Use a dropper to apply a small drop of nitric acid to the scratch. If there is no reaction, then the piece is probably made from real gold.
Answer:
The clear water representing blood, which runs through the
plastic tubes, will become green as particles from the cardboard tube
are absorbed.
Explanation:
the bold letters are answers
Answer:
It would be a form of pollution due to the runoff of chemicals which harm the marine life while helping with the growth of algea more suitably known as
EUTROPHICATION
Explanation:
Answer:
The fraction of heterozygous individuals in the population is 32/100 that equals 0.32 which is the genotipic proportion for these endividuals.
Explanation:
According to Hardy-Weinberg, the allelic frequencies in a locus are represented as p and q, referring to the alleles. The genotypic frequencies after one generation are p² (Homozygous for allele p), 2pq (Heterozygous), q² (Homozygous for the allele q). Populations in H-W equilibrium will get the same allelic frequencies generation after generation. The sum of these allelic frequencies equals 1, this is p + q = 1.
In the exposed example, the r-6 allelic frequency is 0,2. This means that if r-6=0.2, then the other allele frequency (R) is=0.8, and the sum of both the allelic frequencies equals one. This is:
p + q = 1
r-6 + R = 1
0.2 + 0.8 = 1
Then, the genotypic proportion for the homozygous individuals RR is 0.8 ² = 0.64
The genotypic proportion for the homozygous individuals r-6r-6 is 0.2² = 0.04
And the genotypic proportion for heterozygous individuals Rr-6 is 2xRxr-6 = 2 x 0.8 x 0.2 = 0.32
