Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
The limitation in the behavior of lions is that the lions living in a group called a pride , in which lions have strong bond and do not accept a stranger.
<h3>What is pride and how lions behave in social lion group?</h3>
- A study showed that most of the lions living and sharing same geographical area have friendly behavior.
- Pride is a group of lions in which lions interact with each other and share a close bond and do not accept a stranger.
- A pride comprises of total thirty lions at max , above which pride is not a group .
- Behavior like liking , meowing is amongst the friendly behavior lion shows towards other lion.
- The female lions defends the cub , comparatively to the father of the cub.
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Their gametes would have half the number of chromsomes, so 24.
Answer:
C. Ethanol, ammonium chloride, phosphate buffer, magnesium sulfate, calcium chloride, trace elements
Explanation:
Acetobacter must have a sufficient supply of oxygen and cannot grow in its absence. Colonies of acetobacter can be detected by a culture media containing ethanol as carbon source, the acid produce by the bacteria will dissolve the chalk thereby leaving a clear zone around the colony.
