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3 years ago

Brainliest given !! Geometry!! Find the value of h in the triangle. Please provide explanation! Bogus answers reported

Mathematics

2 answers:

s344n2d4d5 [400]3 years ago

8 0

In the figure we have height of the triangle given with their respective sides.

For base 20ft the height of triangle is given as 12 ft.

The area of any triangle = $\frac{1}{2} base times height$

Are of triangle with base 20 ft and height 12 ft = $\frac{1}{2}$ x20x12=120 square ft.

When base of the triangle is 30 ft corresponding height is h ft.

Area of same triangle with base 30 ft and height h ft is

$\frac{1}{2}$ x 30xh=15h square ft

Both are 120 ft and 15h are area of same triangle

We can write 15h=120

Dividing both sides by 15

h=8ft .

evablogger [386]3 years ago

6 0

The answer is 8 ft sorry I can’t explain I can’t even see what I’m typing

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the product of 7 and a number increased by 3 is equal to twice the number subtracted from 39 find the number

Vanyuwa [196]

Say x is the number

7x +3 = 39 -2x
Add 2x to each side
9x +3 =39
Subtract 3 from each side
9x =36
Divide by 9 on each side
x=4

Hope this helped

4 0

4 years ago

Read 2 more answers

Which is the correct way to solve the given equation

Karolina [17]

Option 2. $x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}$ shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form $ax^{2} +bx+c=0$ the solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ .

Here a is the coefficient of $x^{2}$ , b is the coefficient of x and c is the constant term.

$x^{2} -4x=21$ can also be written as $x^{2} -4x-21=0.$

Comparing $x^{2} -4x-21=0$ with $ax^{2} +bx+c=0$ , we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ .

Step 2:

Substituting the values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.$

$\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.$

This is option 2.

7 0

4 years ago

Will give Brainly

g100num [7]

Answer: 33.3%

s Step-by-step explanation: The combined arc length of the red area is 120, which is 1/3 of 360, the full arc. So the probability is 1/3, or 33.3%. Hope this helps!

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3 years ago

Lisa knit a total of 35 centimeters of scarf over 5 nights.How many nights will Lisa have to spend knitting in order to knit a t

jasenka [17]

Answer:

Step-by-step explanation:

I did 35 divided by 5 which is 7. Since it is seven centimeters per night I did 98 divided by 7 which is 14.

5 0

4 years ago

The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit

wolverine [178]

Answer:

(a) $\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

$P(t)=\frac{240t-40t^2}{t^2+20}$

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

$P(t)=\frac{240t-40t^2}{t^2+20}$ using quotient rule.

$\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}$

Simplifying

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

$\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}$

$P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}$

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

$P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}$

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0

3 years ago