Due to apparent doubling of numbers in the question, assume
diameter=13 cm/2=0.065m
h=15 cm=0.15m
rho=5.25*1000=5250 kg/m^3
eta=35%=0.35 [efficiency]
t=12 s
g=3.7 m/s^2
mass, m=rho*V=rho*(4pi/3)(r^3)
=5250 kg/m^3 * (4pi/3)(0.065)^3 m^3
=1.922 kg
Work done in lifting h=0.15m
W=mgh
=1.922pi kg * 3.7 m/s^2 * 0.15 m
=1.067pi kg (m/s)^2
=1.067pi J
Average power required, with efficiency eta=0.35
P=(W/t)/eta
=(1.067pi J )/ (12 s) /0.35
=0.254pi J/s
=0.798W (approx.)
Answer:
x = 6
y = 3
6 twenty-five paisa coin
3 fifty-paisa coins
Step-by-step explanation:
x -----> twenty-five paisa coin
y -----> fifty-paisa coins
0.25x + 0.5y = 3.00 per 100
x = 2y
25x + 50y = 300
x = 2y
25(2y) + 50y = 300
50y + 50y = 300
100y = 300
y = 300/100
y = 3
x = 2y
x = 2(3)
x = 6
Answer:
Using a calculator, we can check that e=2.718281828.
Step-by-step explanation:
Lets evaluate each one of our expression the check which one is closest to e:
(1+ \frac{1}{31} )^{31}=2.675686306
(1+ \frac{1}{32})^{32}=2.676990129
(1+ \frac{1}{34} )^{34}=2.679355428
(1+ \frac{1}{33} )^{33}=2.678207651
We can conclude that the value of (1 +1/34) to the power of 34 is the closest to the value of e.
No it is growth. If it was a fraction the the X power then it would be decay.
The range is correct because its largest to smallest
