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murzikaleks [220]

3 years ago

9

Rosen 15 how many solutions are there to the equation x1 x2 x3 x4 x5

1 answer:

anygoal [31]3 years ago

4 0

<span>The number of answers always corresponds to the highest number of <u>exponents. </u>

Therefore, if <u>x</u></span><u>⁵</u><span><u> is the highest exponent, then there are 5 possible answers</u>.

However, it is important to note that not all of these have real answers for each one. In some cases, an x</span>⁵<span> equation will have a number of real answers and a number of imaginary answers. Nevertheless, they will always add to 5. </span>

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Daniel paid interest of 1,020 in 5years at12%per annum on a loan. Hw much did he borrow

Marat540 [252]

I = Prt
I=1020
r=0.12 (12% converted to decimal by dividing by 100)
t=5
1020=P(0.12)(5)
1020=P(0.6)
P=1700

5 0

3 years ago

Please help I found this one a bit confusing

Sergio [31]

Answer:

C

Step-by-step explanation:

If you look closely.. You can see that one is longer than the other

3 0

3 years ago

Help clear the fractions I need more help

marishachu [46]

Answer:

x = $\frac{43}{6}$

Step-by-step explanation:

Given

$\frac{3}{4}$ x - 5 = $\frac{3}{8}$

Multiply through by 8 ( the LCM of 4 and 8 ) to clear the fractions

6x - 40 = 3 ( add 40 to both sides )

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x = $\frac{43}{6}$

3 0

3 years ago

Select the expression that is equivalent to: 3 root 1089

Delicious77 [7]

Answer:

$3\sqrt{1089}=3\sqrt{3^2(11)^2}$

Step-by-step explanation:

Given : Expression $3\sqrt{1089}$

To find : Select the expression that is equivalent to expression ?

Solution :

Re-write the expression as,

$3\sqrt{1089}=3\sqrt{3\times 3\times 11\times 11}$

$3\sqrt{1089}=3\sqrt{3^2\times 11^2}$

$3\sqrt{1089}=3\sqrt{(3\times 11)^2}$

$3\sqrt{1089}=3\sqrt{(33)^2}$

$3\sqrt{1089}=3\times 33$

$3\sqrt{1089}=99$

The above are the possible equivalent expressions.

7 0

3 years ago

Read 2 more answers

The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea

Sergeeva-Olga [200]

Answer:

(C) $6t^2+5$

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

$d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.$

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

$v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5$

The correct option is C.

6 0

3 years ago