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murzikaleks [220]
3 years ago
9

Rosen 15 how many solutions are there to the equation x1 x2 x3 x4 x5

Mathematics
1 answer:
anygoal [31]3 years ago
4 0
<span>The number of answers always corresponds to the highest number of <u>exponents. </u>

Therefore, if <u>x</u></span><u>⁵</u><span><u> is the highest exponent, then there are 5 possible answers</u>.

However, it is important to note that not all of these have real answers for each one. In some cases, an x</span>⁵<span> equation will have a number of real answers and a number of imaginary answers. Nevertheless, they will always add to 5. </span>
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The fractions of -42/-45 and 14/15 are equivalent
FromTheMoon [43]
Yes, that is true, you have to simplify -42/-45 to be able to see if they are equivalant.
\frac{ - 42}{ - 45} = \frac{14}{15}
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Zina [86]
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How do you calculate percentile in excel? How many students scored lower than 490?
Elina [12.6K]
Calculate rank percentile in Excel

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3 0
3 years ago
Can someone please answer this I don’t understand!
Dovator [93]

The coordinates of X are (5, 11).

Solution:

Given points of the line segment are P(2, 2) and T(7, 17)  

Let X be the point that partitions the directed line segment PT in the ratio 3 : 2

Using section formula, we can find the coordinate of the point that partitions the line segment.

Section formula:

$X(x, y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=2, y_{1}=2, x_{2}=7, y_{2}=17 and m = 3, n =2

Substitute these in the section formula,

$X(x, y)=\left(\frac{3 \times 7+2 \times 2}{3+2}, \frac{3 \times 17+2 \times 2}{3+2}\right)

            $=\left(\frac{21+4}{5}, \frac{51+4}{5}\right)

           $=\left(\frac{25}{5}, \frac{55}{5}\right)

           =(5, 11)

X(x, y) = (5, 11)

The coordinates of X are (5, 11).

6 0
3 years ago
What is the volume of the sphere shown below??<br> R=13
kvasek [131]

Here is your answer

D. \frac{8788}{3}π {units}^{3}

REASON:

Formula for volume of sphere

= 4/3×π× r^3

Here, r= 13

So,

volume=4/3×π× 13^3

= 4/3×π× 2197

= 8788/3 ×π

HOPE IT IS USEFUL

3 0
3 years ago
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