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hjlf
3 years ago
12

Convert 0.0000505 nanometers into scientific notation

Physics
1 answer:
KengaRu [80]3 years ago
4 0
The answer is 5.05x10^-5

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The diagram shows a compressed spring between two carts initially at rest on a horizontal frictionless surface. Cart A has a
EastWind [94]

Answer:

momentum

Explanation:

the impulse is equal for both carts, the momentum for both carts is zero both before the string is cut and after it is cut

6 0
3 years ago
What are the seasonal changes in the weasel in florida and the weasel in wyoming
AlekseyPX
Winter weasels, also called ermines or short-tailed weasels, have coats that turn from light brown to white in the winter. The color change begins at their stomachs and works its way outward, occurring in both spring and fall. Other species, like the long-tailed weasel, may turn at least partially white as well.

The length of daylight, not temperature, prompts the color change. As a result, weasels in winter may be stark white against a brown landscape before snow starts to fall. During warmer winters, this makes them easy prey for larger predators such as foxes, martens, and badgers.

7 0
3 years ago
What is the wavelength of the waves you create in a swimming pool if you splash your hand at a rate of 2.00 Hz and the waves pro
Valentin [98]

Answer:

The wavelength of the waves created in the swimming pool is 0.4 m

Explanation:

Given;

frequency of the wave, f = 2 Hz

velocity of the wave, v = 0.8 m/s

The wavelength of the wave is given by;

λ = v / f

where;

λ is the wavelength

f is the frequency

v is the wavelength

λ = 0.8 / 2

λ = 0.4 m

Therefore, the wavelength of the waves created in the swimming pool is 0.4 m

3 0
3 years ago
You can jump 3 m (10 feet) off of a diving board and into a swimming pool and be uninjured. However, if you jumped from the same
Mrac [35]

Answer:

1) this is due to force due to momentum change of a body falling from such a height.

2) they move with velocity of 2.69 m/s towards the right.

Explanation:

1) in the case where one jumps 3 meters into water, the water deform on impact extending the time of impact for your body's momentum to get to zero, so that the time it takes for the momentum of your body due to your mass and your velocity to get to zero is relatively long lessening the force felt due to the impact.

For a fall from the same height onto a concrete, the concrete does not deform at all. This means that there is a very short time for your momentum to get to zero and hence the force is huge. In order to cushion this a little, your body deforms in a bid to reduce the force and this is very deadly.

This is in line with Newton's second law of motion which states that the rate of change of momentum is proportional to the force produced.

2)

M1 = 125 kg

M2 = 80 kg

V1 = 2.5 m/s

V2 = 3 m/s

From momentum conservation, total initial momentum must be equal to the total momentum after collision.

Momentum = mass x velocity.

That is,

M1V1 + M2V2 = (M1 + M2) Vf

Where Vf is their final velocity together.

Note that the masses stick together because the collision is inelastic.

Substituting and solving, we have

(125 x 2.5) + (80 x 3) = (125 + 80)Vf

312.5 + 240 = 205Vf

552.5 = 205Vf

Vf = 552.5/205 = 2.69 m/s

Note that the linebacker runner has the greater momentum 125 x 2.5 = 312.15

This means they both move to the right at velocity of 2.69 m/s

7 0
3 years ago
6) 100 ml of water is initially at 20°C. 30,000 J of heat is added to the water. What is temperature change for the water?
vovangra [49]
<h2>Δt = 71.67 °C</h2>

The temperature change of water is equal to 71.67 °C

<h3>Explanation:</h3>

Given:

Amount of transferred energy = 30,000 K J

Mass of water = 100 ml

Initial temperature = 20°C

To find the change in temperature of water.

Formula for Heat capacity is given by

Q = m×c×Δt ........................................(1)

where:

Q = Heat capacity of the substance (in J)

m=mass of the substance being heated in grams(g)

c = the specific heat of the substance in J/(g.°C)

Δt = Change in temperature (in °C)

Δt = (Final temperature - Initial temperature) = T(f) - T(i)

Q = 30,000 J

Mass of water = m = 100 ml

1 ml = 1 g ................................................(2)

Therefore m = 100 ml = 100 g

Specific heat of water is c = 4.186 J /g.

Δt = ?

Substituting these in equation (1), we get

Q = m×c×Δt

Rearranging the terms for Δt,

Δt = \frac{Q}{m\times c}

Δt = \frac{30,000}{100\times 4.186}  = \frac{30,000}{418.6}= 71.67\°C

Δt = 71.67 °C

8 0
4 years ago
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