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vladimir1956 [14]
3 years ago
11

Which term describes how quickly a car is slowing down to a stop? Which term describes your location relative to your home? Whic

h term describes how fast and in which direction you are traveling?
Physics
2 answers:
MAXImum [283]3 years ago
6 0

Answer:

Which term describes how quickly a car is slowing down to a stop?

 Acceleration

Which term describes your location relative to your home?

Displacement

Which term describes how fast and in which direction you are traveling?

Velocity

Explanation:

Pavlova-9 [17]3 years ago
3 0

Answer:

Deceleration, Distance And Velocity

<u>Explanation:</u>

  • Deceleration explains the reduction in speed of the car before it comes to stop and it is opposite to acceleration.
  • Distance explains the location of a person from its home and its unit is meter.
  • Velocity explains the relative speed of an object concerning time.
  • It shows both the "magnitude and direction" of the object.
  • Deceleration and Velocity comes under vector quantity and Distance is a scalar quantity.
  • Vector quantity shows the distance covered and the direction of the object
  • Scalar quantity explains the distance moved by the object.
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AlekseyPX
A proton has a positive charge, an electron has a negative charge. Usually, the amount of electrons and protons is the same, but when an electron is lost usually because of radiation or a chemical reaction the resulting amount of electrons/ protons results in a different charge for the atom in general.
When there are more electrons the result it a negative ion, and when there are more protons it is a positive ion. 
So, to answer your question: if an electron is lost from a neutral atom and there are more protons than electrons you get a positive charge. Have a good day!
3 0
4 years ago
Two cars, A and B , travel in a straight line. The distance of A from the starting point is given as a function of time by xA(t)
OLga [1]

A) Car A is initially ahead

B) The two cars are at the same point at the times: t = 0, t = 2.27 s and

t = 5.73 s

C) The distance between the two cars is not changing at t = 1.00 s and t = 4.33 s

D) The two cars have same acceleration at t = 2.67 s

Explanation:

A)

The position of the two cars at time t is given by the following functions:

x_A(t) = \alpha t + \beta t^2

with

\alpha = 2.60 m/s\\\beta = 1.20 m/s^2

Substituting,

x_A(t)=2.60t+1.20 t^2

And

x_B(t)=\gamma t^2 - \delta t^3

with

\gamma=2.80 m/s^2\\\delta = 0.20 m/s^3

Substituting,

x_B(t)=2.80t^2-0.20t^3

Here we want to find which car is ahead just after they leave the starting point. To find that, we just need to calculate the position of the two cars after a very short amount of time, let's say at t = 0.1 s. Substituting this value into the two equations, we get:

x_A(0.1)=2.60(0.1)+1.20(0.1)^2=0.27 m

x_B(0.1)=2.80(0.1)^2-0.20(0.1)^3=0.03 m

So, car A is initially ahead.

B)

The two cars are at the same point when their position is the same. Therefore, when

x_A(t)=x_B(t)

which means when

2.60t+1.20t^2 = 2.80t^2-0.20t^3

Re-arranging the equation, we find

0.20t^3-1.6t^2+2.60t=0\\t(0.20t^2-1.6t+2.60)=0

One solution of this equation is t = 0 (initial point), while we have two more solutions given by the equation

0.20t^2-1.6t+2.60=0

which has two solutions:

t = 2.27 s

t = 5.73 s

So, these are the times at which the cars are at the  same point.

C)

The distance between the two cars A and B is not changing when the velocities of the two cars is the same.

The velocity of car A is given by the derivative of the position of  car A:

v_A(t) = x_A'(t)=(2.60t+1.20t^2)'=2.60+2.40t

The velocity of car B is given by the derivative of the position of car B:

v_B(t)=x_B'(t)=(2.80t^2-0.20t^3)'=5.60t-0.60t^2

Therefore, the distance between the two cars is not changing when the two velocities are equal:

v_A(t)=v_B(t)\\2.60+2.40t=5.60t-0.60t^2\\0.60t^2-3.20t+2.60=0

This is another second-order equation, which has two solutions:

t = 1.00 s

t = 4.33 s

D)

The acceleration of each car is given by the  derivative of the velocity of the car A.

The acceleration of car A is:

a_A(t)=v_A'(t)=(2.60+2.40t)'=2.40

While the acceleration of car B is:

a_B(t)=v_B'(t)=(5.60t-0.60t^2)'=5.60-1.20t

So, the two cars have same acceleration when

a_A(t)=a_B(t)

And solving the equation, we find:

2.40=5.60-1.20t\\1.20t=3.20\\t=2.67 s

So, the two cars have same acceleration at t = 2.67 s.

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Which scenario describes the damage caused by a tornado?
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The answer is a path of destruction up to 50 miles long with destroyed trees and homes.

Tornadoes form from severe thunderstorms. Wind in the higher altitude of the storm moving at a greater velocity than wind at a lower altitude creates a vertical wind shear. The faster-moving winds aloft come from the west and create an updraft when they meet slower-moving wind close to the ground that is moving in the opposite direction. As warm surface air moves upward into the thundercloud, the rotating air creates a vortex.

The image below shows before and after damage of a tornado.

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3 years ago
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Which carbon reservoirs did not receive any carbon?
Allisa [31]
Need a picture of the problem
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3 years ago
4. The winding ridge of a screw​
ZanzabumX [31]

Answer:

Thread.

Explanation:

The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.

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