Question

The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?

Answer 1

Answer: Volume of 1g of pure gold $v=0.05181 \mathrm{cm}^{3}$

Given;

Density of a pure gold=19.3 $g / c m^{3}$

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

     $\rho=m / v$

Where $\rho$=density of pure gold

           m=mass of pure gold

          v=volume of pure gold

From the above equation volume can be calculated as

$v=m / \rho$

Substitute the values of mass and density value in the above equation

$v=1 / 19.3$

$v=0.05181 \mathrm{cm}^{3}$

Result:

Thus the volume of 1g of pure gold is $v=0.05181 \mathrm{cm}^{3}$