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alekssr [168]
3 years ago
5

How many electrons may be accommodated in the first three energy levels?

Chemistry
2 answers:
viktelen [127]3 years ago
3 0
Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. Some points will be nice
ollegr [7]3 years ago
3 0
The first energy level can hold 2 electrons after that all other energy levels hold 8 electrons which means 3 energy levels can hold 18 electrons 2+8+8=18
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Need help with chemistry
AlekseyPX

Answer:

you need to use the 2 because I already did it

Explanation:

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3 0
2 years ago
I need this ASAP thank you
Rainbow [258]

Answer:

16,,24Mg 17,,a24.1 18a mass number of the most abundant isotope

Explanation:

atomic number of Mg is 12 ,therefore its mass number should be the value that is very close to 24.

24.1 is the value of thee most abundant isotope.

8 0
2 years ago
What is the condensation AND freezing point of water C AND F!!
vladimir2022 [97]

Answer:

Condensation 212F or 100C, Freezing 32F or 0C

Explanation:

Condensation 212 degrees Fahrenheit or 100 degrees Celsius.

Freezing point 32 degrees Fahrenheit or 0 degrees Celsius.

4 0
3 years ago
What is the molarity if 2.00 liters containing 49.0 grams of sodium carbonate [Na2CO3)?
yKpoI14uk [10]

Answer: The molarity of solution is 0.231 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Molar mass of Na_2CO_3 = 2\times 22.99+1\times 12.01+3\times 16.00=105.99

moles of Na_2CO_3 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{49.0g}{105.99g/mol}=0.462mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.462mol}{2.00L}

Molarity=0.231M

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5 0
3 years ago
In this double replacement reaction, which are the products? hcl + naoh —> ______?
Anarel [89]
The answer is:  " NaCl + H₂O " ; (or; write as:  " H₂O + NaCl " ) .
________________________________________________________
Specifically:
_________________________________________________________

    HCl + NaOH  —>  NaCl + H₂O  ;   or; write as:

    NaOH + HCl   —>  H₂O + NaCl  .
_______________________________________________________
            This type of "double-replacement" reaction is called "neutralization".
 
             Since we are adding a strong acid to a strong base (reactants), we know that the product will be:  1) a salt ; and 2) water.  Since we know one of the reactants will be "water" (H₂O) ; we can find the base (i.e. , the "remaining product") from selecting the "unused elements" to form the corresponding "salt".
________________________________________________________
3 0
3 years ago
Read 2 more answers
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